This problem involves calculating the annual rate of simple interest (y%) when a series of equal annual instalments are used to pay off a debt over a specific period. The key is to understand that each instalment accrues simple interest from the time it is paid until the end of the debt period.
Let's define the terms involved:
y% per annumThe total amount paid through instalments must equal the total debt. This includes the principal amount of the instalments plus the simple interest accumulated on each.
Since the instalments are paid at the end of each year, they earn simple interest for different durations:
The formula for Simple Interest (SI) is given by $SI = \frac{P \times R \times T}{100}$, where P is the principal, R is the rate, and T is the time.
In this case, the principal for the interest calculation is the instalment amount (₹3,500), and the rate is y%.
The total value of all instalments at the end of the 4-year period is the sum of the principal amounts plus the total interest earned.
Total Value = (Sum of Instalments) + (Total Simple Interest)
Sum of Instalments = $4 \times ₹3,500 = ₹14,000$
Total Simple Interest = Interest on 1st instalment + Interest on 2nd instalment + Interest on 3rd instalment + Interest on 4th instalment
Total Simple Interest = $ (\frac{3500 \times y \times 3}{100}) + (\frac{3500 \times y \times 2}{100}) + (\frac{3500 \times y \times 1}{100}) + (\frac{3500 \times y \times 0}{100}) $
Total Simple Interest = $ \frac{3500 \times y}{100} \times (3 + 2 + 1 + 0) $
Total Simple Interest = $ 35y \times 6 $
Total Simple Interest = $ 210y $
Now, we set the total value (Sum of Instalments + Total Simple Interest) equal to the Total Debt:
$ ₹14,000 + 210y = ₹16,310 $
We need to solve the equation for y:
y by dividing the total interest by the factor calculated:
$ y = \frac{2310}{210} $
Therefore, the rate of simple interest is 11% per annum.
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