This question asks us to find the initial amount of money borrowed (the principal sum). The loan was taken for a duration of 2 years. It was repaid with two equal annual instalments, each amounting to ₹2,260. The loan accrued 5% compound interest, compounded annually. Our goal is to calculate the total sum borrowed and round it to the nearest tens.
When a loan is repaid in equal instalments over a specific period, the original amount borrowed is equivalent to the sum of the present values of all the future instalments. The present value accounts for the time value of money, meaning money received in the future is worth less than money received today due to potential earnings from interest.
Let's define the variables:
The instalments are paid annually at the end of each year. The first instalment is paid at the end of year 1, and the second instalment is paid at the end of year 2. To find their value today (present value), we need to discount them back using the given compound interest rate.
The formula to calculate the present value ($PV$) of a single future payment is:
$$ PV = \frac{\text{Future Value}}{(1+r)^t} $$
Where $t$ is the number of years until the payment is made.
Therefore, the total sum borrowed $S$ is the sum of the present values of the two instalments:
$$ S = \frac{P}{(1+r)^1} + \frac{P}{(1+r)^2} $$
We will now substitute the given values into the formula and perform the calculations:
Given values:
First, let's calculate the value of \(1+r\):
\( 1+r = 1 + 0.05 = 1.05 \)
Now, we calculate the present value of the first instalment, which is paid at the end of year 1:
$$ PV_1 = \frac{2260}{1.05} $$
Next, we calculate the present value of the second instalment, which is paid at the end of year 2:
$$ PV_2 = \frac{2260}{(1.05)^2} $$
Let's calculate $ (1.05)^2 $:
\( (1.05)^2 = 1.1025 \)
Now, we find the numerical values for $PV_1$ and $PV_2$:
\( PV_1 = \frac{2260}{1.05} \approx 2152.38095 \)
\( PV_2 = \frac{2260}{1.1025} \approx 2049.88662 \)
The total sum borrowed $S$ is the sum of these two present values:
$$ S = PV_1 + PV_2 $$
\( S \approx 2152.38095 + 2049.88662 \)
\( S \approx 4202.26757 \)
Alternatively, we can calculate this by factoring out $P$:
$$ S = P \times \left[ \frac{1}{(1+r)^1} + \frac{1}{(1+r)^2} \right] $$
\( S = 2260 \times \left[ \frac{1}{1.05} + \frac{1}{1.1025} \right] \)
\( S = 2260 \times [0.95238095... + 0.90702948...] \)
\( S = 2260 \times 1.85941043... \)
\( S \approx 4202.26757 \)
The question requires the final answer to be rounded to the nearest tens. Our calculated sum borrowed is approximately ₹4202.27.
To round ₹4202.27 to the nearest tens:
Therefore, ₹4202.27 rounded to the nearest tens is ₹4,200.
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