This question involves calculating the size of equal annual installments needed to repay a loan taken under compound interest. We are given:
We need to find the amount of each equal installment, let's call it 'x'. The core idea is that the original loan amount must be equal to the sum of the present values of all the installments paid back.
When a loan is repaid in equal installments, it can be treated as an annuity. The formula connecting the Present Value (PV) of the loan to the equal installment amount (x), interest rate per period (r), and the number of periods (n) is derived from the present value of an ordinary annuity formula:
\(PV = x \times \frac{1 - (1 + r)^{-n}}{r}\)
Where:
Let's substitute the given values into the formula:
So, the equation becomes:
\(10,000 = x \times \frac{1 - (1 + 0.10)^{-3}}{0.10}\)
First, calculate the value of \((1 + r)^{-n}\):
\((1 + 0.10)^{-3} = (1.1)^{-3}\)
\((1.1)^3 = 1.331\)
\((1.1)^{-3} = \frac{1}{1.331} \approx 0.751315\)
Next, calculate the term in the fraction (the annuity factor):
\(\frac{1 - (1.1)^{-3}}{0.10} = \frac{1 - 0.751315}{0.10}\)
\(= \frac{0.248685}{0.10}\)
\(= 2.48685\)
Now, we can find the installment amount 'x' by rearranging the formula:
\(x = \frac{PV}{\text{Annuity Factor}}\)
\(x = \frac{10,000}{2.48685}\)
Performing the final division:
\(x \approx 4021.14\)
The calculation shows that the amount of each installment is approximately ₹4,021.14. Looking at the options provided, 4,021 is the closest approximation.
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