Aman goes to his office by car at the speed of 80 km/hr and reaches 10 minutes earlier. If he goes at the speed 30 km/hr, then he reaches 10 minutes late. What will be the speed of the car to reach on time?
480/11 km/hr
Let the distance be D km. Difference in times = 10 + 10 = 20 minutes = \(\frac{1}{3}\) hour.
\(\frac{D}{30} - \frac{D}{80} = \frac{1}{3}\)
\(\frac{8D - 3D}{240} = \frac{1}{3}\)
5D = 80
D = 16 km
Correct time = \(\frac{16}{80}\) hour + 10 minutes
= \(\frac{1}{5} + \frac{1}{6} = \frac{11}{30}\) hour
Required speed = 16 ÷ \(\frac{11}{30}\)
= \(\frac{480}{11}\) km/hr
Hence, 480/11 km/hr.
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