Problem Analysis:
Key Geometric Principle:
The angle subtended by an arc at the centre of a circle is double the angle subtended by the same arc at any point on the circumference. In this case, arc BC subtends $\angle BOC$ at the centre O and $\angle BAC$ at the circumference (point A).
Applying the Principle:
In an equilateral triangle, each interior angle measures $60^\circ$. Therefore:
$ \angle BAC = 60^\circ $
Using the angle theorem:
$ \angle BOC = 2 \times \angle BAC $
Calculation:
Note: The side length of 6 cm is not required to determine the angle $\angle BOC$.
Conclusion:
The angle $\angle BOC$ is $120^\circ$. This corresponds to Option D.
ABCDEF is a regular hexagon. Side of the hexagon is 36 cm. What is the area of the triangle AOB ?
If ∆ABC ~ ∆DEF, and BC = 4 cm, EF = 5 cm and the area of triangle ABC = 80 cm 2, then the area of the triangle DEF is:
If Δ ABC is right angled at B, AB = 12 cm and ∠CAB = 60°, determine the length of BC.
If ΔABC and ΔDEF are congruent triangles, then which of the following is FALSE?
D and E are points on the sides AB and AC, respectively, of ΔABC such that DE is parallel to BC and AD ∶ DB = 7 ∶ 9. If CD and BE intersect each other at F. then find the ratio of areas of ΔDEF and ΔCBF.