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Question

A uniform motion of a car along a circular path experiences

This question was previously asked in
NDA I 2021 GAT Previous Year Paper (18-Apr-2021)
The correct answer is

a change in velocity due to a change in its direction of motion.

Understanding Uniform Circular Motion

Uniform circular motion describes the movement of an object in a circular path at a constant speed. While the speed remains constant, other physical quantities associated with the object's motion might change.

Analyzing Motion Along a Circular Path

Let's break down the properties of motion for a car moving uniformly along a circular path:

  • Speed: This is the magnitude of velocity. In uniform circular motion, the speed is constant. For example, if the car is moving at a steady 30 km/h around a roundabout, its speed is constant.
  • Velocity: This is a vector quantity that includes both speed and direction. Even if the speed is constant, if the direction of motion changes, the velocity changes. In circular motion, the car's direction is continuously changing as it follows the curve of the circle. The velocity vector is always tangent to the circular path at any given point. Since the direction is changing, the velocity is changing.
  • Momentum: This is also a vector quantity defined as the product of mass and velocity ($\vec{p} = m\vec{v}$). Since the mass of the car is constant, any change in velocity will result in a change in momentum. As we established, the velocity changes in circular motion because its direction changes. Therefore, the momentum also changes.

Evaluating the Options

Let's examine each option based on our understanding of uniform circular motion:

  1. a change in speed due to a change in its direction of motion.

    This option is incorrect. In uniform circular motion, the speed is constant, not changing. The change in direction affects velocity, not speed.

  2. a change in velocity due to a change in its direction of motion.

    This option is correct. While the speed (magnitude of velocity) is constant, the direction of velocity is continuously changing as the car moves in a circle. Because velocity is a vector, a change in direction means a change in the velocity vector itself. This change in velocity is indeed due to the change in the direction of motion.

  3. a change in momentum due to no change in its direction of motion.

    This option is incorrect. Momentum changes because velocity changes ($\vec{p} = m\vec{v}$). Velocity changes because the direction of motion changes. The statement incorrectly claims there is "no change in its direction of motion."

  4. a constant momentum due to a change in its direction of motion.

    This option is incorrect. Momentum is $\vec{p} = m\vec{v}$. Since the velocity vector is changing (due to the changing direction), the momentum vector is also changing, not constant.

In summary, uniform circular motion implies constant speed but continuously changing velocity and momentum because the direction of motion is constantly changing.

Quantity In Uniform Circular Motion Reason
Speed Constant Definition of uniform motion
Velocity Changing Direction is continuously changing
Momentum ($\vec{p} = m\vec{v}$) Changing Mass is constant, Velocity is changing
Direction of Motion Continuously Changing Moving in a circle

Revision Table: Key Concepts in Uniform Circular Motion

Review the following terms related to circular motion:

  • Uniform Circular Motion: Movement along a circular path at constant speed.
  • Speed: Scalar magnitude of velocity; constant in uniform circular motion.
  • Velocity: Vector quantity (speed + direction); changes in circular motion due to changing direction.
  • Momentum: Vector quantity (mass × velocity); changes in circular motion because velocity changes.

Additional Information: Centripetal Acceleration and Force

The change in velocity in circular motion means there is acceleration. This acceleration is always directed towards the center of the circle and is called centripetal acceleration.

  • Centripetal Acceleration ($\vec{a}_c$): Causes the change in the direction of velocity. Its magnitude is constant in uniform circular motion ($a_c = \frac{v^2}{r}$, where $v$ is speed and $r$ is the radius), but its direction is always towards the center, thus changing.
  • Centripetal Force ($\vec{F}_c$): According to Newton's second law ($\vec{F} = m\vec{a}$), a net force is required to cause this centripetal acceleration. This force is also directed towards the center of the circle. For a car turning in a circle, this force is often provided by friction between the tires and the road.

Both centripetal acceleration and force are present and are essential for maintaining the circular path, even when the speed is uniform.

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Similar Questions

  1. A bicycle racing track is a level circular road of radius 10 m. Three cyclists P, Q and R with identical cycles are cycling on the track with speeds 2 m/s, 3 m/s and 5 m/s respectively. If the coefficient of friction between the tyres and the road is 0.1, then which cyclist will slip? (Take \(g = 10 \, m/s^2\))

  2. What is the minimum horizontal speed given to the bob of a simple pendulum of length 50 cm so that it describes a complete circle? (Take \(g = 10\ m/s^2\))


Important Questions from Circular motion

  1. A particle is moving in a circle with uniform speed. It has constant

  2. Suppose a boy is enjoying a ride on a merry - go -round which is moving with a constant speed of 10 ms-1. It implies that the boy is -

  3. The circumference of a planet is 36,000 km. If the planet makes no other movement and takes 20 hours for one complete rotation, what is the speed of a point on its equator?

  4. In a chamber, a uniform magnetic field of 4.5 G (1G = 10-4 T) is maintained. An electron is shot into the field with a speed of 4.8 × 106 m/s normal to the field. Find the radius of the circular orbit? Also obtain the frequency of revolution of the electron in its circular orbit? (e = 1.6 × 10- 19 C, me = 9.1 × 10-31 kg) choose an approximate value

  5. The vehicle moving on a level circular path will exert pressure such that _____.

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