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Question

A toy is in the form of a solid cone having a radius of 5 cm and a height of 12 cm. It is mounted on a frustum of a solid cone, with the toy’s vertex pointed upwards, and the frustum’s smaller base having a radius of 5 cm. The larger base of the frustum has a radius of 22 cm. The slant height of the frustum is 32 cm. What is the total surface area (in cm2) of the toy?

This question was previously asked in
RRB ALP 2025 CBT 2 Wiremen Question Paper (28-Jul-2026) (Shift 2)
The correct answer is

$1413\pi$

The toy consists of two parts: a solid cone and a frustum. The total surface area of the toy is the sum of the curved surface area of the cone, the curved surface area of the frustum, and the area of the larger base of the frustum.

1. Calculate Cone Details

Given:

  • Cone radius (\(r_1\)) = 5 cm
  • Cone height (\(h_1\)) = 12 cm

Calculate the slant height (\(l_1\)) of the cone using the Pythagorean theorem:

\(l_1 = \sqrt{r_1^2 + h_1^2}\)

\(l_1 = \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169} = 13 \text{ cm}\)

Calculate the Curved Surface Area (CSA) of the cone:

\(CSA_{\text{cone}} = \pi r_1 l_1\)

\(CSA_{\text{cone}} = \pi \times 5 \times 13 = 65\pi \text{ cm}^2\)

2. Calculate Frustum Details

Given:

  • Frustum smaller base radius (\(r_1\)) = 5 cm
  • Frustum larger base radius (\(r_2\)) = 22 cm
  • Frustum slant height (\(l_2\)) = 32 cm

Calculate the Curved Surface Area (CSA) of the frustum:

\(CSA_{\text{frustum}} = \pi (r_1 + r_2) l_2\)

\(CSA_{\text{frustum}} = \pi (5 + 22) \times 32 = \pi \times 27 \times 32 = 864\pi \text{ cm}^2\)

Calculate the Area of the larger base of the frustum:

\(Area_{\text{base}} = \pi r_2^2\)

\(Area_{\text{base}} = \pi \times 22^2 = 484\pi \text{ cm}^2\)

3. Calculate Total Surface Area

The total surface area (TSA) of the toy is:

\(TSA = CSA_{\text{cone}} + CSA_{\text{frustum}} + Area_{\text{base}}\)

\(TSA = 65\pi + 864\pi + 484\pi\)

\(TSA = (65 + 864 + 484)\pi\)

\(TSA = 1413\pi \text{ cm}^2\)

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