The tank initially contains 120 litres of liquid.
The percentage of alcohol is 30%.
Initial amount of alcohol = $30\%$ of 120 litres
Initial alcohol = $\frac{30}{100} \times 120 = 0.30 \times 120 = 36$ litres.
Initial amount of non-alcohol = $120 - 36 = 84$ litres.
30 litres of the mixture are removed.
Amount of alcohol removed = $30\%$ of 30 litres
Alcohol removed = $\frac{30}{100} \times 30 = 9$ litres.
Amount of non-alcohol removed = $30 - 9 = 21$ litres.
Amount of alcohol remaining = $36 - 9 = 27$ litres.
Amount of non-alcohol remaining = $84 - 21 = 63$ litres.
Total volume remaining = $120 - 30 = 90$ litres.
30 litres of another liquid are added.
This new liquid contains 50% alcohol.
Amount of alcohol added = $50\%$ of 30 litres
Alcohol added = $\frac{50}{100} \times 30 = 15$ litres.
Amount of non-alcohol added = $30 - 15 = 15$ litres.
Total alcohol in the resulting solution = Alcohol remaining + Alcohol added
Total alcohol = $27 + 15 = 42$ litres.
Total volume of the resulting solution = Volume remaining + Volume added
Total volume = $90 + 30 = 120$ litres.
Percentage of alcohol in the resulting solution = $\frac{\text{Total alcohol}}{\text{Total volume}} \times 100\%
Percentage of alcohol = $\frac{42}{120} \times 100\%
Percentage of alcohol = $\frac{420}{12}\% = 35\%$.
A container has 60 litres of a mixture of acid and water in the ratio 7:3. 20% of the mixture is taken out and replaced with water. This operation is repeated once more. What is the final percentage of acid in the mixture?
My father is presently 25 years older than me. The sum of our ages 5 years ago was 39 years. Find my present age.
Rice worth ₹43/kg and ₹67/kg are mixed with a third variety in the ratio 2 : 1 : 5. If the mixture is worth ₹96/kg, the price (in ₹) of the third variety of rice per kg will be:
42 litres of milk at ₹25 per litre is mixed with 28 litres of milk at ₹40 per litre. Find the average price of the mixture.
15 kg of ₹10 per kg wheat is mixed with 5 kg of another type of wheat to get a mixture costing ₹30 per kg. Find the price (per kg) of the costlier wheat.
If a + b + c = 0, then the value of (a² + b² + 2ab) is equal to: