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Question

A 45-litre mixture of kerosene and diesel contains kerosene and diesel in the ratio 4:5. How much diesel must be added to make the ratio 4:6?

This question was previously asked in
SSC CGL 2025 Tier 1 Question Paper (25-Sep-2025) (Shift 3)
The correct answer is
5 L

Initial Mixture Analysis

The total volume of the mixture is 45 litres.

The initial ratio of kerosene to diesel is 4:5.

  • Total ratio parts = 4 + 5 = 9 parts.
  • Volume per ratio part = $\frac{45 \text{ L}}{9} = 5$ L.
  • Initial quantity of kerosene = $4 \times 5 \text{ L} = 20$ L.
  • Initial quantity of diesel = $5 \times 5 \text{ L} = 25$ L.

Final Mixture Calculation

Diesel is added to the mixture, so the quantity of kerosene remains constant.

  • Kerosene in the final mixture = 20 L.
  • The target ratio of kerosene to diesel is 4:6.
  • Let the final quantity of diesel be '$D_{final}$'.
  • Set up the ratio equation: $\frac{\text{Kerosene}}{\text{Diesel}} = \frac{4}{6}$
  • Substitute the known values: $\frac{20 \text{ L}}{D_{final}} = \frac{4}{6}$
  • Solve for '$D_{final}$': $4 \times D_{final} = 20 \text{ L} \times 6$ $D_{final} = \frac{120 \text{ L}}{4}$ $D_{final} = 30$ L.

Diesel Added Amount

Calculate the amount of diesel that needs to be added.

  • Diesel to be added = Final diesel quantity - Initial diesel quantity
  • Diesel to be added = $30 \text{ L} - 25 \text{ L}$
  • Diesel to be added = 5 L.

Therefore, 5 litres of diesel must be added.

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Important Questions from Mixture and Alligation

  1. My father is presently 25 years older than me. The sum of our ages 5 years ago was 39 years. Find my present age.

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  5. If a + b + c = 0, then the value of (a² + b² + 2ab) is equal to:

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