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Question

A standard multiplexed 6 by 4 LED matrix contains a total of _______ independent light-emitting nodes, which can be fully operated using a minimum of _______ microcontroller control pins.

This question was previously asked in
RRB ALP 2025 CBT 2 Wiremen Question Paper (28-Jul-2026) (Shift 2)
The correct answer is

24; 10

To answer this question, we need to understand how a multiplexed LED matrix works and how to determine the number of independent light-emitting nodes and the microcontroller control pins required.

Understanding a Multiplexed LED Matrix

A multiplexed 6 by 4 LED matrix is a grid of LEDs arranged in 6 rows and 4 columns. The total number of independent light-emitting nodes is the product of the number of rows and columns.

Calculations for the total independent nodes:

  • Number of rows: 6
  • Number of columns: 4
  • Total light-emitting nodes = 6 * 4 = \(24\)

Hence, the total number of independent light-emitting nodes in the matrix is 24.

Determining Necessary Microcontroller Control Pins

For a multiplexed LED matrix, you need to control each row and each column separately, which typically requires one control pin per row and one per column.

Calculations for control pins:

  • Control pins for rows: 6
  • Control pins for columns: 4
  • Total control pins required = 6 + 4 = \(10\)

Therefore, a minimum of 10 microcontroller control pins are required to operate a 6 by 4 LED matrix.

Conclusion

From the calculations, we conclude that:

  • The total number of independent light-emitting nodes is 24.
  • The minimum number of microcontroller control pins needed is 10.

Based on the explanation above, the correct answer is: 24; 10.

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Similar Questions

  1. A PN junction diode that ____ when activated is called a/an _______.

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Important Questions from LED Lights

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