A sphere of radius $r$ cm is packed in a box of cubical shape.
What should be the minimum volume (in $cm^3$) of the box that can enclose the sphere?
To find the minimum volume of a cubical box that can enclose a sphere, we need to determine the smallest possible dimensions of the cube.
The volume of a cube is calculated as side length cubed ($V = s^3$).
Thus, the minimum volume of the cubical box required is $8r^3$ cubic centimeters.
The minimum volume required for the cubical box is achieved when its side length is exactly equal to the diameter of the sphere ($2r$). The volume calculation $(2r)^3$ correctly yields $8r^3$. Other options represent volumes that are too small to enclose the sphere.
In the given figure, PQRS is a square of side 2 cm and PLMN is a rectangle. The corner L of the rectangle is on the side QR. Side MN of the rectangle passes through the corner S of the square.
What is the area (in cm²) of the rectangle PLMN?
Note: The figure shown is representative.

A regular dodecagon (12-sided regular polygon) is inscribed in a circle of radius $r$ cm as shown in the figure. The side of the dodecagon is $d$ cm. All the triangles (numbered 1 to 12) in the figure are used to form squares of side $r$ cm and each numbered triangle is used only once to form a square.
The number of squares that can be formed and the number of triangles required to form each square, respectively, are:
Note: The figure shown is representative.