This problem involves understanding how multiple sequential discounts affect the final selling price and how profit is calculated based on the cost price. We need to find the profit percentage if the item was sold after only the first discount, given the final selling price after three discounts and the overall profit.
Key terms:
Let's break down the calculation step-by-step to determine the profit:
Assume the Marked Price (MP) of the article is '\(M\)'. The shopkeeper applies three consecutive discounts: 10%, 20%, and 25%.
First, calculate the price after the 10% discount:
\(SP_1 = M \times \left(1 - \frac{10}{100}\right) = M \times (1 - 0.10) = 0.90M\)
Next, apply the 20% discount to the resulting price (\(SP_1\)):
\(SP_2 = SP_1 \times \left(1 - \frac{20}{100}\right) = 0.90M \times (1 - 0.20) = 0.90M \times 0.80 = 0.72M\)
Finally, apply the 25% discount to the price \(SP_2\) to get the final Selling Price (SP):
\(SP = SP_2 \times \left(1 - \frac{25}{100}\right) = 0.72M \times (1 - 0.25) = 0.72M \times 0.75 = 0.54M\)
This means the final selling price is 54% of the marked price.
We are told that this final selling price (\(SP = 0.54M\)) results in a profit of 8% on the Cost Price (CP). The relationship between SP, CP, and profit percentage is:
\(SP = CP \times \left(1 + \frac{\text{Profit \%}}{100}\right)\)
Substitute the known values:
\(0.54M = CP \times \left(1 + \frac{8}{100}\right)\)
\(0.54M = CP \times (1 + 0.08)\)
\(0.54M = 1.08 \times CP\)
Now, solve for the Cost Price (CP) in terms of the Marked Price (M):
\(CP = \frac{0.54M}{1.08}\)
\(CP = \frac{54}{108} M = \frac{1}{2} M = 0.50M\)
Therefore, the cost price is exactly half of the marked price.
The question asks for the profit if the article had been sold after only the *first* discount of 10%. From Step 1, we found this selling price (\(SP_1\)) to be:
\(SP_1 = 0.90M\)
To find the profit in this scenario, we compare the selling price \(SP_1\) with the cost price \(CP\). We have \(SP_1 = 0.90M\) and \(CP = 0.50M\).
The profit would be:
\(\text{Profit} = SP_1 - CP\)
\(\text{Profit} = 0.90M - 0.50M = 0.40M\)
Now, calculate the profit percentage using the profit and the cost price:
\(\text{Profit \%} = \frac{\text{Profit}}{\text{CP}} \times 100\)
\(\text{Profit \%} = \frac{0.40M}{0.50M} \times 100\)
The variable '\(M\)' cancels out:
\(\text{Profit \%} = \frac{0.40}{0.50} \times 100 = \frac{4}{5} \times 100\)
\(\text{Profit \%} = 0.8 \times 100 = 80\%\)
The calculated profit percentage, if the article were sold after only the first discount, is 80%. We compare this result with the given options:
Since 80% is not listed among the first three options, the correct choice is "None of the above".
A person sells article X for ₹34,500 and makes a profit of 15%. He sells article Y at a loss of 10%. He neither loses nor gains on the whole because of these two transactions. What is the selling price of article Y?
A shopkeeper sold his goods at the cost price. By using false weights, he gained \(11\frac{1}{9}\%\). What weight did he use for 1 kg?
The ratio of the cost price of two articles X and Y is \(1:2\). A businessman earns a profit of \(p\%\) by selling X and a loss of \(3p\%\) by selling Y. If he loses \(20\%\) in this transaction, then what is the value of \(p\)?
Rohit buys 8 pens and 4 pencils for Rs. 2400. He sells pencils at a profit of 20 percent and pens at the loss of 10 percent. If his overall profit is Rs. 240, then what is the sum of the cost price of one pen and one pencil?
A man sells a car to his friend at the loss of 10 %; who in return sells it for Rs. 54000 making a profit of 20 %. What was the initial value of the car?
An article was sold at a loss of 24%. If it were sold for Rs. 1,596 more, then there would have been a gain of 18%, The cost price of the article is:
The cost price of an article is Rs.6,450. If it sold at a profit 16%, how much would be its selling price?
If the selling price of 7 articles is equal to the cost price of 6 articles, then what is the percentage loss?