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Question

A seller professes to sell his fruits at cost price but still gains \(5\frac{5}{19}\)%. How much does he give for 1 kg?

This question was previously asked in
SSC CGL 2023 (Tier-II) Paper 1 Previous Year Paper (26-Oct-2023) (Shift-1)
The correct answer is

950 gm

Understanding False Weight Profit Problems

This problem deals with a dishonest seller who claims to sell goods at the cost price but uses a false weight to make a profit. The profit is earned because the seller charges the price of a larger quantity (like 1 kg) while actually selling a smaller quantity.

Let's assume the cost price (CP) of 1 kg (1000 gm) of fruits is \(C\). The seller professes to sell at this cost price.

However, the seller gives a smaller weight, let's say \(W\) grams, instead of 1000 grams.

The seller charges the price of 1000 gm, which is \(C\), for only \(W\) grams of fruits. So, the selling price (SP) of \(W\) grams is \(C\).

The actual cost price of \(W\) grams of fruits is \(C \times \frac{W}{1000}\).

The gain is the difference between the selling price and the actual cost price for the quantity sold:

Gain = SP of \(W\) gm - CP of \(W\) gm

Gain = \(C - C \times \frac{W}{1000} = C \left(1 - \frac{W}{1000}\right)\)

The gain percentage is calculated on the actual cost price of the quantity sold (which is \(W\) gm):

Gain% = \(\frac{\text{Gain}}{\text{CP of W gm}} \times 100\)

Gain% = \(\frac{C \left(1 - \frac{W}{1000}\right)}{C \times \frac{W}{1000}} \times 100\)

We can cancel \(C\) from the numerator and denominator:

Gain% = \(\frac{1 - \frac{W}{1000}}{\frac{W}{1000}} \times 100\)

Gain% = \(\frac{\frac{1000 - W}{1000}}{\frac{W}{1000}} \times 100\)

Gain% = \(\frac{1000 - W}{W} \times 100\)

Calculating the Given Gain Percentage

The problem states the seller gains \(5\frac{5}{19}\)%. Let's convert this mixed fraction percentage into an improper fraction:

\(5\frac{5}{19}\)% = \(\frac{5 \times 19 + 5}{19}\)% = \(\frac{95 + 5}{19}\)% = \(\frac{100}{19}\)%

Solving for the Weight Given

Now we set up the equation using the gain percentage formula and the given value:

\(\frac{1000 - W}{W} \times 100 = \frac{100}{19}\)

Divide both sides by 100:

\(\frac{1000 - W}{W} = \frac{1}{19}\)

Cross-multiply:

\(19 \times (1000 - W) = 1 \times W\)

\(19000 - 19W = W\)

Add \(19W\) to both sides:

\(19000 = W + 19W\)

\(19000 = 20W\)

Solve for \(W\):

\(W = \frac{19000}{20}\)

\(W = \frac{1900}{2}\)

\(W = 950\)

So, the seller gives 950 grams for 1 kg.

Verification and Conclusion

The calculation shows that the seller gives 950 gm while charging for 1000 gm. This matches one of the options provided.

The calculated weight is 950 gm.

Concept Details
Claimed Sale Price Cost price of 1000 gm
Actual Weight Sold \(W\) gm
Actual Cost Price of Sold Weight CP of \(W\) gm
Gain Source Difference between price of 1000 gm and cost of \(W\) gm
Gain Percentage Calculation Base Actual cost price of \(W\) gm

Revision Table: Key Concepts in False Weight Problems

Term Explanation
False Weight Using a weight less than what is indicated or charged for.
Gain % (False Weight) \(\frac{\text{Error}}{\text{Actual Weight Used}} \times 100\)
Error True Weight - Actual Weight Used (e.g., 1000 gm - W gm)
Selling at Cost Price Claim Charging the buyer the cost price of the advertised weight (e.g., cost of 1000 gm).

Additional Information: Profit Calculation Variations

In profit and loss problems, the gain or loss percentage is usually calculated on the cost price. In false weight scenarios where the seller claims to sell at cost price, the gain comes purely from the difference in weight supplied versus weight charged for. The formula used above, \(\frac{\text{Error}}{\text{Actual Weight}} \times 100\), is a direct application of the gain percentage formula where the 'gain' is proportional to the 'error' in weight, and the base for percentage calculation is the 'actual weight' supplied (as this is the quantity whose cost is effectively recovered plus a profit).

If a seller claims to sell at a profit/loss percentage while using a false weight, the calculation becomes a bit more complex, combining both the declared profit/loss and the gain/loss from the weight difference.

Understanding the base on which the percentage is calculated (usually CP, but effectively the cost of the actual quantity sold in false weight cases at CP) is crucial for solving these problems.

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Similar Questions

  1. A shopkeeper gains 20% in place of 16% loss if the selling price of an article is increased by Rs. 324. The cost price of the article is:

  2. A table was bought for Rs. 3,000 and sold for Rs. 3,200. Find the gain or loss in terms of money.

  3. By selling a watch for Rs. 2,000, a shopkeeper loses 20%. How much would he gain or lose by selling it for Rs. 3,000?

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  5. The marked price on a book is ₹1,000. In a book fair, it is available for sale with a discount scheme offering two successive discounts of 12% and 8%. What is the final selling price (in ₹) of the book for a customer (rounded off to the nearest integer)?

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Important Questions from Profit and Loss

  1. Ram bought a chair at 35% discount on its market price, Had Ram got no discount, he would have had to pay ₹245 more. How much did Ram pay for the chair? 

  2. A shopkeeper bought an item for Rs. 4,500 and sold it at a loss of 5%. From this money, he bought another item and sold it at a profit of 10%. What is his overall profit?

  3. A man sells two articles at Rs. 9,180 each. He gains 8% on one article and loses 15% on the other. His overall profit or loss is:

  4. A shopkeeper selling an article for ₹46 loses 8%. In order to gain 6%, what should be the selling price of the article?

  5. Rahul purchased 80 items from the market. 25% items of the total items were defective and the remaining items were sold at 50% profit. What will be the overall profit percentage?

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