We are given the radius of a sector, $r = 14 \text{ cm}$, and its area, $A = 154 \text{ cm}^2$. We need to find the angle of the sector, $\theta$.
The formula for the area of a sector is:
$ A = \frac{\theta}{360^\circ} \pi r^2 $
Where:
Substitute the known values into the formula:
$ 154 = \frac{\theta}{360^\circ} \times \frac{22}{7} \times (14)^2 $
$ 154 = \frac{\theta}{360^\circ} \times \frac{22}{7} \times 196 $
$ \frac{22}{7} \times 196 = 22 \times \frac{196}{7} = 22 \times 28 = 616 $
$ 154 = \frac{\theta}{360^\circ} \times 616 $
$ \theta = \frac{154 \times 360^\circ}{616} $
$ \theta = \frac{154 \times 360^\circ}{4 \times 154} $
$ \theta = \frac{360^\circ}{4} $
$ \theta = 90^\circ $
The angle of the sector is $90^\circ$. This corresponds to Option A.
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