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Question

A rectangle becomes a square when its length and breadth are reduced by 10 m and 5 m, respectively. During this process, the rectangle loses 650 m² of area. What is the area of the original rectangle in square meters?

The correct answer is
2250

Rectangle Reduction Scenario

We are given a rectangle. When its length is decreased by 10 m and its breadth by 5 m, it transforms into a square. This transformation also results in a loss of 650 m² from the original area.

Equations from Conditions

Let the original length of the rectangle be $L$ meters and the original breadth be $B$ meters.

The original area of the rectangle is $A_{orig} = L \times B$. After the reductions, the new length is $L-10$ and the new breadth is $B-5$. Since the new shape is a square, its sides must be equal:

$ L - 10 = B - 5 \quad (1) $

The new area is $A_{new} = (L-10)(B-5)$. The problem states that the area loss is 650 m²:

$ A_{orig} - A_{new} = 650 $ $ (L \times B) - (L-10)(B-5) = 650 \quad (2) $

Dimensions Solved

We solve the system of equations to find the original dimensions:

  1. From equation (1), we express $L$ in terms of $B$: $ L = B - 5 + 10 $ $ L = B + 5 $
  2. Substitute this expression for $L$ into equation (2): $ ((B+5) \times B) - ((B+5-10) \times (B-5)) = 650 $ $ (B^2 + 5B) - ((B-5) \times (B-5)) = 650 $
  3. Expand and simplify the equation: $ (B^2 + 5B) - (B^2 - 10B + 25) = 650 $ $ B^2 + 5B - B^2 + 10B - 25 = 650 $ $ 15B - 25 = 650 $
  4. Solve for $B$: $ 15B = 650 + 25 $ $ 15B = 675 $ $ B = \frac{675}{15} $ $ B = 45 \text{ m} $
  5. Calculate $L$ using $L = B + 5$: $ L = 45 + 5 $ $ L = 50 \text{ m} $

Original Area Calculation

Now, calculate the area of the original rectangle using the found dimensions $L=50$ m and $B=45$ m:

$ \text{Original Area} = L \times B $ $ \text{Original Area} = 50 \text{ m} \times 45 \text{ m} $ $ \text{Original Area} = 2250 \text{ m}^2 $

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Important Questions from Mensuration and Geometry

  1. The city of Atlantis was crafted by the God of the seas, Poseidon. It was made of alternating concentric circular rings of land (shaded) and water (not shaded) as represented in the figure (not to scale). The radius of Inner Island was 2.5 stades (a unit of length used in ancient Greece). The water surrounding Inner Island was one stade wide (length AB). This was surrounded by two pairs of alternating rings of land and water. The first pair of land and water was two stades wide each (lengths BC and CD), and the outer pair is three stades wide each (lengths DE and EF).
    The ratio of the surface area of the land to that of the water in the city of Atlantis is _________ (round off to two decimal places).

  2. In the given figure, $P, Q$, and $R$ are three points on a circle of radius 10 cm with $O$ as its center, $\overline{PQ} = \overline{RQ}$, and $\angle PQR = 45^\circ$. The figure is representative.
    The area of the shaded region $PQRO$ is ______________ cm$^2$.

  3. A straight line $y = x - 1$ intersects a circle with center at $x = 1, y = 1$ and radius of magnitude 1 at two points. The length of the chord formed by this intersection is _______. (rounded off to three decimal places)
  4. The shell of a hollow spherical nanoparticle has a uniform thickness of 3 nanometers (nm). The outer radius of the nanoparticle is 5 nm. The ratio of the volume of the shell to the volume of the hollow core is ________
    (Round off to one decimal place)
  5. The volume of a sphere of diameter 1 unit is ______ than the volume of a cube of side 1 unit.
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