A person borrowed ₹2,000 at 5% annual simple interest repayable in 3 equal annual installments. What will be the annual installment?
₹730\(\frac{10}{63}\)
This question asks us to find the equal annual installment amount required to repay a simple interest loan.
We are given:
Let the equal annual installment amount be \(x\).
In simple interest installment problems, the total amount due at the end of the loan period (if no payments were made) is equal to the sum of the future values of all the installments paid, calculated using the simple interest formula.
The simple interest future value formula is: \(FV = P(1 + \frac{RT}{100})\), where \(P\) is the present value (the installment amount in this case), \(R\) is the rate, and \(T\) is the time from the payment date to the end of the loan term.
Step 1: Calculate the total amount due at the end of 3 years without any installments.
Total Simple Interest = \(\frac{P \times R \times T}{100}\)
Total Simple Interest = \(\frac{2000 \times 5 \times 3}{100} = \frac{30000}{100} = 300\)
Total Amount Due = Principal + Total Simple Interest
Total Amount Due = \(2000 + 300 = 2300\)
So, if the loan were repaid as a single sum at the end of 3 years, the total amount payable would be ₹2,300.
Step 2: Calculate the future value of each installment at the end of the loan term (after 3 years).
Step 3: Equate the total amount due to the sum of the future values of the installments.
Sum of Future Values of Installments = \(1.10x + 1.05x + x = 3.15x\)
Total Amount Due = Sum of Future Values of Installments
\(2300 = 3.15x\)
Step 4: Solve for \(x\).
\(x = \frac{2300}{3.15}\)
To remove the decimal, multiply the numerator and denominator by 100:
\(x = \frac{2300 \times 100}{3.15 \times 100} = \frac{230000}{315}\)
Now, simplify the fraction by dividing the numerator and denominator by their greatest common divisor. Both are divisible by 5:
\(230000 \div 5 = 46000\)
\(315 \div 5 = 63\)
So, \(x = \frac{46000}{63}\)
Step 5: Convert the fraction to a mixed number to match the options.
Divide 46000 by 63:
| 7 | 3 | 0 | |
|---|---|---|---|
| 63 | 46000 | ||
| -441 | |||
| --- | |||
| 190 | |||
| -189 | |||
| ---- | |||
| 10 | 0 | ||
| -0 | |||
| -- | |||
| 10 |
The quotient is 730, and the remainder is 10. So, the mixed number is \(730 \frac{10}{63}\).
Thus, the annual installment amount is ₹\(730 \frac{10}{63}\).
The annual installment amount is ₹\(730 \frac{10}{63}\).
Let's verify the answer by converting the option back to an improper fraction:
\(730 \frac{10}{63} = \frac{(730 \times 63) + 10}{63} = \frac{45990 + 10}{63} = \frac{46000}{63}\).
This matches our calculated value for \(x\).
| Concept | Description | Formula |
|---|---|---|
| Simple Interest (SI) | Interest calculated only on the principal amount. | \(SI = \frac{P \times R \times T}{100}\) |
| Amount (A) | Total sum of principal and interest. | \(A = P + SI = P(1 + \frac{RT}{100})\) |
| Principal (P) | The initial amount borrowed or invested. | |
| Rate (R) | The percentage at which interest is charged or earned per unit of time (usually per annum). | |
| Time (T) | The duration for which the principal is borrowed or invested. |
It's important to distinguish between simple interest and compound interest when dealing with loan installments.
This question specifically mentioned "simple interest", guiding us to use the simple interest method described in the solution.
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