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Question

A person borrowed ₹2,000 at 5% annual simple interest repayable in 3 equal annual installments. What will be the annual installment?

The correct answer is

₹730\(\frac{10}{63}\)

Calculating Simple Interest Loan Installments

This question asks us to find the equal annual installment amount required to repay a simple interest loan.

We are given:

  • Principal amount (P) = ₹2,000
  • Annual simple interest rate (R) = 5%
  • Number of equal annual installments (n) = 3

Let the equal annual installment amount be \(x\).

Understanding Simple Interest Installments

In simple interest installment problems, the total amount due at the end of the loan period (if no payments were made) is equal to the sum of the future values of all the installments paid, calculated using the simple interest formula.

The simple interest future value formula is: \(FV = P(1 + \frac{RT}{100})\), where \(P\) is the present value (the installment amount in this case), \(R\) is the rate, and \(T\) is the time from the payment date to the end of the loan term.

Step-by-Step Calculation of the Installment Amount

Step 1: Calculate the total amount due at the end of 3 years without any installments.

Total Simple Interest = \(\frac{P \times R \times T}{100}\)

Total Simple Interest = \(\frac{2000 \times 5 \times 3}{100} = \frac{30000}{100} = 300\)

Total Amount Due = Principal + Total Simple Interest

Total Amount Due = \(2000 + 300 = 2300\)

So, if the loan were repaid as a single sum at the end of 3 years, the total amount payable would be ₹2,300.

Step 2: Calculate the future value of each installment at the end of the loan term (after 3 years).

  • The first installment is paid at the end of Year 1. It earns simple interest for the remaining 2 years (from end of Year 1 to end of Year 3).
  • Future Value of 1st Installment = \(x(1 + \frac{5 \times 2}{100}) = x(1 + 0.10) = 1.10x\)
  • The second installment is paid at the end of Year 2. It earns simple interest for the remaining 1 year (from end of Year 2 to end of Year 3).
  • Future Value of 2nd Installment = \(x(1 + \frac{5 \times 1}{100}) = x(1 + 0.05) = 1.05x\)
  • The third installment is paid at the end of Year 3. It earns simple interest for 0 years.
  • Future Value of 3rd Installment = \(x(1 + \frac{5 \times 0}{100}) = x(1 + 0) = x\)

Step 3: Equate the total amount due to the sum of the future values of the installments.

Sum of Future Values of Installments = \(1.10x + 1.05x + x = 3.15x\)

Total Amount Due = Sum of Future Values of Installments

\(2300 = 3.15x\)

Step 4: Solve for \(x\).

\(x = \frac{2300}{3.15}\)

To remove the decimal, multiply the numerator and denominator by 100:

\(x = \frac{2300 \times 100}{3.15 \times 100} = \frac{230000}{315}\)

Now, simplify the fraction by dividing the numerator and denominator by their greatest common divisor. Both are divisible by 5:

\(230000 \div 5 = 46000\)

\(315 \div 5 = 63\)

So, \(x = \frac{46000}{63}\)

Step 5: Convert the fraction to a mixed number to match the options.

Divide 46000 by 63:

730
6346000
-441
---
190
-189
----
100
-0
--
10

The quotient is 730, and the remainder is 10. So, the mixed number is \(730 \frac{10}{63}\).

Thus, the annual installment amount is ₹\(730 \frac{10}{63}\).

Summary of the Simple Interest Installment Calculation

The annual installment amount is ₹\(730 \frac{10}{63}\).

Let's verify the answer by converting the option back to an improper fraction:

\(730 \frac{10}{63} = \frac{(730 \times 63) + 10}{63} = \frac{45990 + 10}{63} = \frac{46000}{63}\).

This matches our calculated value for \(x\).

Revision Table: Simple Interest Key Concepts

ConceptDescriptionFormula
Simple Interest (SI)Interest calculated only on the principal amount.\(SI = \frac{P \times R \times T}{100}\)
Amount (A)Total sum of principal and interest.\(A = P + SI = P(1 + \frac{RT}{100})\)
Principal (P)The initial amount borrowed or invested.
Rate (R)The percentage at which interest is charged or earned per unit of time (usually per annum).
Time (T)The duration for which the principal is borrowed or invested.

Additional Information: Simple Interest vs. Compound Interest Installments

It's important to distinguish between simple interest and compound interest when dealing with loan installments.

  • Simple Interest Installments: Interest is typically calculated based on the initial principal amount for the full term or on the reducing balance *before* the installment is applied for that year. The method used in the solution (equating future value of total amount due to sum of future values of installments) is a common approach for simple interest installment problems.
  • Compound Interest Installments: Interest is calculated on the principal amount plus any accumulated interest from previous periods. The calculation involves concepts like present value or future value of annuities, and the formula \(EMI = P \times \frac{r(1+r)^n}{(1+r)^n - 1}\) (for Equated Monthly Installments) or similar annual installment formulas based on compounding. Compound interest installments are more common in real-world lending scenarios.

This question specifically mentioned "simple interest", guiding us to use the simple interest method described in the solution.

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Important Questions from Installments

  1. A sum of Rs. 4,620 is to be paid back in 2 equal annual instalments. How much is each instalment (in Rs.) if the interest is compounded annually at 10% per annum?

  2. Surekha borrowed a sum of money and returned it in two equal annual installments of Rs. 5,547 each. If the rate of interest was \(7 \frac{1}{2}\%\)  p.pa compounded yearly, then the total interest paid by her was:

  3. A loan is to be returned in two equal yearly instalments. If the rate of interest is 10% p.a., compounded annually, and each instalment is Rs. 5,808, then the total interest charged in this scheme is:

  4. What annual instalment will discharge a debit of ₹5,664 in 4 years at 12% simple interest?

  5. A sum of Rs. P was borrowed and paid back in two equal yearly instalments, each of Rs. 35,280. If the rate of interest was 5% compounded annually, then the value of P is:

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