Let the two-digit number be represented as $10x + y$, where $x$ is the tens digit and $y$ is the units digit.
First, simplify the second equation:
$10x + y - 45 = 10y + x$ $10x - x + y - 10y = 45$ $9x - 9y = 45$Divide the entire equation by 9:
$x - y = 5 \quad (2)$Now, we have a system of two linear equations:
Add equation (1) and equation (2) to eliminate $y$:
$(x + y) + (x - y) = 9 + 5$ $2x = 14$ $x = \frac{14}{2}$ $x = 7$Substitute the value of $x$ (which is 7) back into equation (1):
$7 + y = 9$ $y = 9 - 7$ $y = 2$The tens digit ($x$) is 7 and the units digit ($y$) is 2.
The number is $10x + y = 10(7) + 2 = 70 + 2 = 72$.
Therefore, the number is 72.
If $\oplus \div \odot = 2$, $\oplus \div \triangle = 3$, $\odot + \triangle = 5$, and $\Delta \times \otimes = 10$,
then the value of $(\otimes - \oplus)^2$ is: