Ankita has to climb 5 stairs starting at the ground, while respecting the following rules:
1. At any stage, Ankita can move either one or two stairs up.
2. At any stage, Ankita cannot move to a lower step.
Let $F(N)$ denote the number of possible ways in which Ankita can reach the $N^{th}$ stair. For example, $F(1) = 1$, $F(2) = 2$, $F(3) = 3$. The value of $F(5)$ is ________.
Ankita needs to climb 5 stairs. She starts at the ground (step 0). At each step, she can either climb 1 stair or 2 stairs up. She cannot move down. We need to find the total number of distinct ways ($F(5)$) she can reach the 5th stair.
Let $F(N)$ be the number of ways to reach the $N^{th}$ stair. To reach the $N^{th}$ stair, Ankita must have come from either the $(N-1)^{th}$ stair (by taking a single step) or the $(N-2)^{th}$ stair (by taking two steps). Therefore, the total number of ways to reach the $N^{th}$ stair is the sum of the ways to reach the $(N-1)^{th}$ stair and the ways to reach the $(N-2)^{th}$ stair.
The recurrence relation is: $F(N) = F(N-1) + F(N-2)$
We are given the values for the first few stairs:
Now, we use the recurrence relation to find $F(4)$ and $F(5)$:
Thus, there are 8 possible ways for Ankita to reach the 5th stair.
If $\oplus \div \odot = 2$, $\oplus \div \triangle = 3$, $\odot + \triangle = 5$, and $\Delta \times \otimes = 10$,
then the value of $(\otimes - \oplus)^2$ is: