A 'frabjous' number is a 3-digit number where all digits are odd, and no adjacent digits are the same.
The odd digits are: 1, 3, 5, 7, 9. There are 5 odd digits available.
We need to determine the number of choices for each of the three positions (hundreds, tens, units).
To find the total number of possible frabjous numbers, we multiply the number of choices for each digit:
Total Numbers = (Choices for hundreds digit) $\times$ (Choices for tens digit) $\times$ (Choices for units digit)
Total Numbers = $5 \times 4 \times 4$
Total Numbers = $80$
Therefore, there are 80 such frabjous numbers.
If $\oplus \div \odot = 2$, $\oplus \div \triangle = 3$, $\odot + \triangle = 5$, and $\Delta \times \otimes = 10$,
then the value of $(\otimes - \oplus)^2$ is:
Ankita has to climb 5 stairs starting at the ground, while respecting the following rules:
1. At any stage, Ankita can move either one or two stairs up.
2. At any stage, Ankita cannot move to a lower step.
Let $F(N)$ denote the number of possible ways in which Ankita can reach the $N^{th}$ stair. For example, $F(1) = 1$, $F(2) = 2$, $F(3) = 3$. The value of $F(5)$ is ________.