A mixture of chemicals contains chemical X and chemical Y. If 3 L of chemical Y is added, chemical X becomes 40%. If 3 L of chemical X is added instead, chemical X becomes 50%. Find the initial quantity of the mixture.
27 L
Let initial mixture be V litres with X litres of chemical X, so X/V is the initial fraction.
Adding 3 L of Y: X / (V + 3) = 0.40, so X = 0.4(V + 3).
Adding 3 L of X: (X + 3) / (V + 3) = 0.50, so X + 3 = 0.5(V + 3).
Subtracting: 3 = 0.1(V + 3), so V + 3 = 30 and V = 27 L.
Hence, the answer is 27 L.
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Important Questions from Mixture Problems
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- A trader mixes 255 kg of rice at Rs.170 per kg with 265 kg of rice of other variety at Rs. 170 per kg and sells the mixture at Rs.204 per kg. Find his profit percent.
5 litres are drawn from a cask full of wine and is then filled with water. This operation is performed once more. The ratio of the quantity of wine now left in cask to that of the water is 16:9. How much wine the cask hold originally? (In litres)
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