A Mathematics problem is given to two students X and Y to solve. The odds in favour of X solving the problem are 6 to 9 and the odds against Y in solving the problem are 6 to 5. What is the probability that the problem will be solved if both X and Y try to solve the problem?
\(\dfrac{37}{55}\)
The odds in favour of X give \(P(X) = \dfrac{6}{6+9} = \dfrac{2}{5}\), and the odds against Y give \(P(Y) = \dfrac{5}{6+5} = \dfrac{5}{11}\). The probability that the problem is solved by at least one of them is \(1-\left(1-\dfrac{2}{5}\right)\left(1-\dfrac{5}{11}\right) = 1-\dfrac{3}{5}\times\dfrac{6}{11} = 1-\dfrac{18}{55} = \dfrac{37}{55}\).
If n > 7, then what is the probability that C(n, 7) is a multiple of 7?
Three candidates solve a question. Odds in favour of the correct answer are 5 : 2, 4 : 3 and 3 : 4 respectively for the three candidates. What is the probability that at least two of them solve the question correctly?
The problem of statistics is given in two sections of same standard. The odds against for section x to slove the problem are 4 ∶ 3 and odds in favour to section Y for solving the same problems are 7 ∶ 8. The probability that neither section solves the problem of statistics, if both sections try independent of each other, is:
If n > 7, then what is the probability that C(n, 7) is a multiple of 7?
Three candidates solve a question. Odds in favour of the correct answer are 5 : 2, 4 : 3 and 3 : 4 respectively for the three candidates. What is the probability that at least two of them solve the question correctly?