(Rounded off to two decimal places)
To determine the average speed for the entire journey, we need to calculate the total distance covered and the total time consumed. The average speed is defined as the total distance divided by the total time.
The formula used is:
$ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} $
The journey consists of two parts, each with a different distance and speed. We need to find the time taken for each part separately using the formula:
$ \text{Time} = \frac{\text{Distance}}{\text{Speed}} $
$ t_1 = \frac{d_1}{s_1} = \frac{200 \text{ km}}{50 \text{ km/hr}} = 4 \text{ hours} $
$ t_2 = \frac{d_2}{s_2} = \frac{300 \text{ km}}{60 \text{ km/hr}} = 5 \text{ hours} $
Next, we sum the distances and times from both segments to find the overall values for the journey:
Now, we apply the average speed formula using the calculated total distance and total time:
$ \text{Average Speed} = \frac{D}{T} = \frac{500 \text{ km}}{9 \text{ hours}} $
Performing the division:
$ \text{Average Speed} \approx 55.555... \text{ km/hr} $
The question requires the answer to be rounded off to two decimal places.
Rounding $55.555...$ to two decimal places, we get $ \bf{55.56} $ km/hr.
So, the man's average speed for the entire journey is approximately 55.56 km/hr.
A and B have to travel from place P to place Q following the same route in their respective cars. A drives at $60$ kmph while B drives at $80$ kmph. Find the time taken by B to reach place Q if A takes $12$ hrs.
On a straight road, a bus is $60$ km ahead of a car running in the same direction. After $3$ hours, the car is $90$ km ahead of the bus. If the speed of the bus is $45$ km/h, then what is the speed of the car (in km/h)?
A train running at the speed of $90$ kmph crosses a $250$ m long platform in $26$ seconds. What is the length of the train (in m)?
A car covers 4 successive stretches of 3 km each at speed of 10 kmph, 20 kmph, 30 kmph and 60 kmph respectively. The average speed of the car for the entire journey is: