A car covers 4 successive stretches of 3 km each at speed of 10 kmph, 20 kmph, 30 kmph and 60 kmph respectively. The average speed of the car for the entire journey is:
The question asks for the average speed of a car over a journey consisting of four equal distances covered at different speeds. Average speed is not simply the average of the individual speeds. Instead, it's calculated by dividing the total distance traveled by the total time taken.
The journey is divided into four equal stretches, each 3 km long. The speeds for these stretches are different:
The total distance is the sum of the distances of all stretches.
Total Distance = Distance$_1$ + Distance$_2$ + Distance$_3$ + Distance$_4$
Total Distance = 3 km + 3 km + 3 km + 3 km
Total Distance = 4 $\times$ 3 km = 12 km
To find the average speed, we first need to calculate the time taken for each stretch using the formula:
Time = $\frac{\text{Distance}}{\text{Speed}}$
Let's calculate the time for each stretch:
Now, we sum these times to find the total time:
Total Time = \(t_1\) + \(t_2\) + \(t_3\) + \(t_4\)
Total Time = 0.3 + 0.15 + 0.1 + 0.05 hours
Total Time = 0.6 hours
Finally, we use the formula for average speed:
Average Speed = $\frac{\text{Total Distance}}{\text{Total Time}}$
Plugging in our calculated values:
Average Speed = $\frac{12 \text{ km}}{0.6 \text{ hours}}$
Average Speed = 20 kmph
| Stretch | Distance (km) | Speed (kmph) | Time (hours) |
|---|---|---|---|
| 1 | 3 | 10 | 0.3 |
| 2 | 3 | 20 | 0.15 |
| 3 | 3 | 30 | 0.1 |
| 4 | 3 | 60 | 0.05 |
| Total | 12 | -- | 0.6 |
The calculations show that the total distance covered is 12 km, and the total time taken is 0.6 hours. Therefore, the average speed for the entire journey is 20 kmph.
With a certain set of diameters, a tractor's front wheels make 2 revolutions (revs) for every 1 revolution of the rear wheels. The effect of changing wheel diameter(s) is shown in the following plot. 
In this context, which of the following statements is CORRECT?