A man starts from point A and travels 3 km towards the east to reach B and then turns left and travels thrice the distance to reach another point C. From there he again turns left and travels five times the distance he covered between A and B and reaches his destination D. What is the shortest distance between the starting point and his destination?
15 km
Let A be the origin (0, 0). Travelling 3 km east reaches B at (3, 0).
Turning left from east means facing north; travelling thrice the AB distance, that is 9 km, reaches C at (3, 9).
Turning left again from north means facing west; travelling five times the AB distance, that is 15 km, reaches D at \(3 - 15 = -12\), so D is at (-12, 9).
The shortest distance AD is \(\sqrt{(-12-0)^2 + (9-0)^2} = \sqrt{144 + 81} = \sqrt{225} = 15\) km.
A man walks from his home to office. From home he walks 6 km west, then he turns to his right and walk 5 km, again he turns to his right and walk 10 km, again he turns right and walk 1 km and he turns left and walk 1 km and finally takes a right turn and walk 4 km to reach his office. Where is his office with respect to home?
What is the direction of U with respect to P?
What is the shortest distance between R and T?
If a person walks 3m towards the North from point V, takes a right turn and walks for another 15m, which of the following points would he reach?
In which direction is Amit facing at point F?
What is the distance between the starting point and the end point?