A man is 24 years older than his son. In two years, his age will be twice the age of his son. What is the present age of the son?
22 years
22 years is correct.
Let the son's present age be \(x\) years. Then the man's present age is \(x + 24\) years.
In two years the son will be \(x + 2\) and the man \(x + 26\), and the man's age will be twice the son's: \(x + 26 = 2(x + 2)\).
\(x + 26 = 2x + 4 \Rightarrow x = 22\).
Check: the son is 22 and the man 46 now; in two years they are 24 and 48, and 48 is twice 24. Hence, the son's present age is 22 years.
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