A man can row at 9 km/h in still water. When the river flows at 5 km/h, it takes him 2.4 hours to row to a certain place and return. How far is the place? (Rounded off to 2 decimal places)
7.47 km
Downstream speed = still-water speed + stream speed \(= 9 + 5 = 14\text{ km/h}\). Upstream speed \(= 9 - 5 = 4\text{ km/h}\).
Let the one-way distance be D km. Total time for the round trip: \(\dfrac{D}{14} + \dfrac{D}{4} = 2.4\).
Take the common denominator 28: \(\dfrac{2D}{28} + \dfrac{7D}{28} = \dfrac{9D}{28} = 2.4\).
Solve for D: \(D = \dfrac{2.4 \times 28}{9} = \dfrac{67.2}{9} \approx 7.47\text{ km}\).
Hence, the place is approximately 7.47 km away.
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