Let the total distance of the run be represented by D kilometers.
The first water station is reached after covering $\frac{1}{7}$th of the total distance. The medical aid is found after covering an additional $\frac{1}{6}$th of the total distance.
To add the fractions:
$ \frac{1}{7} + \frac{1}{6} = \frac{6}{42} + \frac{7}{42} = \frac{13}{42} $So, the medical aid station is located at $\frac{13}{42}D$ from the start.
A second runner joins the race 4 km after the medical-aid station. This means the second runner starts at a position of $(\frac{13}{42}D + 4)$ km.
The second runner stops 4 km before the completion of the run. This means the second runner's stopping point is at $(D - 4)$ km.
The distance covered by this second runner is given as $\frac{1}{2}$ of the total distance, which is $\frac{1}{2}D$.
The distance covered by the second runner can also be expressed as the difference between their stopping point and starting point:
$ (\text{Stopping Point}) - (\text{Starting Point}) = \text{Distance Covered} $ $ (D - 4) - (\frac{13}{42}D + 4) = \frac{1}{2}D $Simplify the equation:
$ D - 4 - \frac{13}{42}D - 4 = \frac{1}{2}D $ $ D - \frac{13}{42}D - 8 = \frac{1}{2}D $Combine the terms involving D on one side:
$ D - \frac{13}{42}D - \frac{1}{2}D = 8 $Find a common denominator (42) for the fractions:
$ \frac{42}{42}D - \frac{13}{42}D - \frac{21}{42}D = 8 $ $ (\frac{42 - 13 - 21}{42})D = 8 $ $ (\frac{8}{42})D = 8 $ $ \frac{4}{21}D = 8 $Solve for D:
$ D = 8 \times \frac{21}{4} $ $ D = 2 \times 21 $ $ D = 42 $The total distance of the run is 42 km.
A and B have to travel from place P to place Q following the same route in their respective cars. A drives at $60$ kmph while B drives at $80$ kmph. Find the time taken by B to reach place Q if A takes $12$ hrs.
On a straight road, a bus is $60$ km ahead of a car running in the same direction. After $3$ hours, the car is $90$ km ahead of the bus. If the speed of the bus is $45$ km/h, then what is the speed of the car (in km/h)?
A train running at the speed of $90$ kmph crosses a $250$ m long platform in $26$ seconds. What is the length of the train (in m)?
A car covers 4 successive stretches of 3 km each at speed of 10 kmph, 20 kmph, 30 kmph and 60 kmph respectively. The average speed of the car for the entire journey is: