The core principle to understand here is the concept of independent events in probability.
The fact that the die landed on six three times in a row does not change the inherent probabilities for the *next* throw.
For a fair die, the probability of rolling any specific number (like a six) is calculated as:
$P(\text{Specific Outcome}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$In this case, for rolling a six:
$P(\text{rolling a 6}) = \frac{1}{6}$Since the next throw is independent of the previous ones, the probability of getting a six remains the same as it was for the first throw.
Therefore, the probability of getting a six on the next throw is $1/6$.
A canal system is shown in the figure.

Water flows from A to B through two channels. Gates $G_1$ and $G_2$ are operated independently to regulate the flow. Probability of $G_1$ to be open is 10% while that of $G_2$ is 20%. The probability that water will flow from A to B is