The core principle to understand here is the concept of independent events in probability.
The fact that the die landed on six three times in a row does not change the inherent probabilities for the *next* throw.
For a fair die, the probability of rolling any specific number (like a six) is calculated as:
$P(\text{Specific Outcome}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$In this case, for rolling a six:
$P(\text{rolling a 6}) = \frac{1}{6}$Since the next throw is independent of the previous ones, the probability of getting a six remains the same as it was for the first throw.
Therefore, the probability of getting a six on the next throw is $1/6$.
The following bus schedule is seen at a bus stop located somewhere in between town A and town B.
Town A-00:10, then every 20 mins
Town B-00:15, then every 20 mins
If a person arrives at this bus stop at some random time, the probability that the next bus is for town B is