A current of 1.0 A is drawn by a filament of an electric bulb for 10 minutes. The amount of electric charge that flows through the circuit is
600 C
This question asks us to calculate the amount of electric charge that flows through the filament of an electric bulb. We are given the electric current flowing through the filament and the duration for which the current flows.
Electric current is defined as the rate of flow of electric charge. In simple terms, it tells us how much charge passes a point in a circuit per unit time. The relationship between electric current, charge, and time is fundamental in physics.
The relationship between current ($I$), electric charge ($Q$), and time ($t$) is given by the formula:
\( I = \frac{Q}{t} \)
Where:
To find the amount of electric charge (\( Q \)), we can rearrange the formula:
\( Q = I \times t \)
We are given the following information:
Before calculating the charge, we need to ensure all units are consistent with the SI system. The current is in Amperes (A), which is the SI unit. However, the time is given in minutes, which is not the standard SI unit for time in this context. The SI unit for time is seconds (s).
To convert minutes to seconds, we use the conversion factor: 1 minute = 60 seconds.
So, 10 minutes can be converted as follows:
\( t = 10 \text{ minutes} \times 60 \frac{\text{seconds}}{\text{minute}} \)
\( t = 600 \text{ seconds} \)
Now that we have the current in Amperes and the time in seconds, we can use the formula \( Q = I \times t \) to calculate the electric charge.
\( Q = 1.0 \text{ A} \times 600 \text{ s} \)
\( Q = 600 \text{ C} \)
Therefore, the amount of electric charge that flows through the circuit in 10 minutes is 600 Coulombs.
| Quantity | Given Value | Units | Conversion | Value in SI Units |
|---|---|---|---|---|
| Current (\( I \)) | 1.0 | A | None needed | 1.0 A |
| Time (\( t \)) | 10 | minutes | \( 1 \text{ minute} = 60 \text{ seconds} \) | \( 10 \times 60 = 600 \text{ s} \) |
| Charge (\( Q \)) | Unknown | C | Formula: \( Q = I \times t \) | \( 1.0 \text{ A} \times 600 \text{ s} = 600 \text{ C} \) |
The calculated amount of electric charge is 600 C.
| Concept | Formula | Units |
|---|---|---|
| Electric Current (\( I \)) | \( \frac{Q}{t} \) | Amperes (A) |
| Electric Charge (\( Q \)) | \( I \times t \) | Coulombs (C) |
| Time (\( t \)) | \( \frac{Q}{I} \) | Seconds (s) |
Electric current is a scalar quantity, but its direction is conventionally taken as the direction of flow of positive charge. In most conductors, like the filament of a bulb, the current is due to the flow of negatively charged electrons, which move in the opposite direction of the conventional current.
One Coulomb (1 C) of charge is the amount of charge transported by a constant current of one Ampere (1 A) in one second (1 s). This unit is named after Charles-Augustin de Coulomb, a French physicist.
The Ampere (A) is defined based on the force between two parallel current-carrying conductors. It is one of the seven base units of the International System of Units (SI).
Understanding the relationship \( Q = I \times t \) is crucial for solving many problems involving electric circuits and quantifying the amount of charge moved over time by a steady current.
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