A current I flows through a resistor. A source maintains a potential difference of V across the resistor. The energy supplied by the source in time t is:
V I t
Let's break down how to find the energy supplied by a source to a resistor when a current flows through it. We are given the potential difference (\(V\)) across the resistor, the current (\(I\)) flowing through it, and the time (\(t\)) for which the current flows.
The electrical power (\(P\)) supplied to a component in a circuit is directly proportional to both the potential difference (\(V\)) across it and the current (\(I\)) flowing through it. The fundamental formula for electrical power is:
\[P = V \times I\]
This formula tells us the rate at which energy is being supplied or consumed in the circuit component at any given moment.
Energy is the total amount of power supplied or consumed over a specific period of time. If power (\(P\)) is constant over a time interval (\(t\)), the total energy (\(E\)) supplied or consumed is given by the formula:
\[E = P \times t\]
This means if power is measured in watts (which is joules per second) and time in seconds, the energy will be in joules.
Now, we can combine the two formulas we have:
Substitute the expression for power (\(P = V \times I\)) from the first formula into the second formula:
\[E = (V \times I) \times t\]
So, the energy (\(E\)) supplied by the source in time (\(t\)) when a potential difference (\(V\)) is maintained across a resistor and a current (\(I\)) flows through it is:
\[E = VIt\]
Let's compare our derived formula with the given options:
Our derived formula \(E = VIt\) matches the third option.
| Quantity | Formula(s) | Units |
|---|---|---|
| Potential Difference (Voltage) | \(V\) (Given) | Volts (V) |
| Current | \(I\) (Given) | Amperes (A) |
| Time | \(t\) (Given) | Seconds (s) |
| Power | \(P = VI\) | Watts (W) |
| Energy Supplied | \(E = Pt = VIt\) | Joules (J) |
The energy dissipated in a resistor is converted into heat. This phenomenon is described by Joule's Law of Heating. The heat energy (\(H\)) produced in a resistor with resistance \(R\) when a current \(I\) flows through it for time \(t\) is given by:
\[H = I^2Rt\]
Using Ohm's Law, which states \(V = IR\), we can express this energy formula in other ways:
All three expressions for energy/heat \((VIt, I^2Rt, V^2t/R)\) are equivalent and represent the energy supplied by the source and dissipated by the resistor in time \(t\).
Electric current is considered to be the flow of _________.
When a number of resistors are connected in series in a circuit, the value of current ________ across each resistor.
The resistance of a conductor is inversely proportional to:
If a body takes ‘t’ seconds to go once around the circular path of radius ‘r’, the velocity ‘v’ is given by
If the resistance of a conductor is doubled, the current gets halved. This is because:
In a Class 2 lever, effort and load move in the:
Two identical resistors, each of 10 Ω, are connected in parallel. This combination, in turn, is connected to a third resistor in series of 10 Ω. The equivalent resistance of the combination is ________.
If the power of a corrective lens in +2.0D, then it is a:
Insulators have resistivity of the order of ________.
A curved mirror where the reflecting surface is curved inwards is called a ________.
What special name is given to the frictional force exerted by a fluid?
______ is used in periscope.
Zero degree centigrade is equal to what degree Fahrenheit?
A. 100°F
B. 30°F
C. 34°F
D. 32°F
Keeping voltage constant, if more lamps are put into a series circuit, the overall current in the circuit:
A. Increases
B. Decreases
C. Remains the same
D. Becomes infinite
Excessive curvature of eye lens leads to _______