All Exams Test series for 1 year @ ₹349 only
Question

A cube with a mass of 5.74 g occupies a volume of 1.2 cm³. The density (in g/cm³) expressed with the correct number of significant figures is ______.

This question was previously asked in
RRB NTPC 2024 Undergraduate CBT 1 Question Paper (29-Aug-2025) (Shift 1)
The correct answer is

4.8

To calculate the density of the cube, we use the formula:

Density \(= \frac{\text{Mass}}{\text{Volume}}\)

Given:

  • Mass = 5.74 g
  • Volume = 1.2 cm³

Substituting the values into the formula:

Density \(= \frac{5.74 \text{ g}}{1.2 \text{ cm}^3} \approx 4.78333 \text{ g/cm}^3\)

However, we must consider significant figures. The least number of significant figures in the given values is 2 (in 1.2 cm³). Therefore, the final answer must also have 2 significant figures. Rounding 4.78333 to two significant figures gives 4.8 g/cm³.

Therefore, the density of the cube, expressed with the correct number of significant figures, is 4.8 g/cm³.

Was this answer helpful?

Important Questions from Miscellaneous - Physics

  1. What does PCB stand for in electric circuits?
  2. What are the streams of charged particles ejected by the Sun into space called?
Need Expert Advice?
Upcoming Exams
RRB NTPC
September 27, 2026
Test Series
RRB ALP img
Railways
RRB ALP 2026 Mock Test series
1035 Tests 1 Tests Free
886 Attempts
4.3(235)
English, Hindi
More Questions from RRB ALP

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App