A cube of side 49 cm is painted purple on all the faces and then cut into smaller cubes of sides 7 cm each. Find the number of smaller cubes having only one face printed.
150
This problem involves a large cube that is painted and then cut into many smaller identical cubes. We need to determine how many of these smaller cubes have paint on exactly one of their faces.
Let the side length of the large cube be \(L\) and the side length of the smaller cubes be \(s\).
Given:
First, we need to find out how many smaller cubes fit along one edge of the large cube. This number, let's call it \(n\), is given by:
\[ n = \frac{L}{s} \]
Substituting the given values:
\[ n = \frac{49 \, \text{cm}}{7 \, \text{cm}} = 7 \]
So, the large cube is cut into \(7 \times 7 \times 7\) smaller cubes.
The total number of smaller cubes is \(n^3 = 7^3 = 343\).
When a large cube is painted on all its faces and then cut, the smaller cubes will have different numbers of painted faces depending on their original position in the large cube:
We are interested in the smaller cubes that have only one face painted. These are the cubes that were originally on the faces of the large cube, away from the edges and corners.
Consider one face of the original large cube. This face is a square grid of \(n \times n\) smaller cube faces. In our case, it's a \(7 \times 7\) grid.
The smaller cubes on this face that have only one painted face are those that are not on the edges of this face grid. On a \(7 \times 7\) grid, the cubes along the edges are those in the first and last rows, and the first and last columns.
The number of cubes along one edge is \(n\). The number of cubes along each edge that are *not* corners is \((n-2)\). There are 12 edges on a cube, so there are \(12 \times (n-2)\) edge cubes (2 painted faces).
The cubes on the face that have only one painted face form an inner square on that face. The dimensions of this inner square are \((n-2) \times (n-2)\).
For our case, \(n=7\), so the inner square on one face contains \((7-2) \times (7-2) = 5 \times 5 = 25\) smaller cubes.
Each of these 25 cubes is located on one specific face of the large cube and has only that face painted.
A cube has 6 faces. Since each face contributes \((n-2)^2\) cubes with one painted face, the total number of smaller cubes with only one painted face is:
\[ \text{Number of one-faced cubes} = 6 \times (n-2)^2 \]
Substituting \(n=7\):
\[ \text{Number of one-faced cubes} = 6 \times (7-2)^2 \]
\[ \text{Number of one-faced cubes} = 6 \times (5)^2 \]
\[ \text{Number of one-faced cubes} = 6 \times 25 \]
\[ \text{Number of one-faced cubes} = 150 \]
Therefore, there are 150 smaller cubes having only one face painted.
| Cube Type | Location | Number of Painted Faces | Formula (for n>2) | Calculation (n=7) | Count |
|---|---|---|---|---|---|
| Corner Cubes | Corners | 3 | 8 | 8 | 8 |
| Edge Cubes | Edges (not corners) | 2 | \(12 \times (n-2)\) | \(12 \times (7-2) = 12 \times 5\) | 60 |
| Face Cubes | Faces (not edges/corners) | 1 | \(6 \times (n-2)^2\) | \(6 \times (7-2)^2 = 6 \times 5^2 = 6 \times 25\) | 150 |
| Inner Cubes | Inside | 0 | \((n-2)^3\) | \((7-2)^3 = 5^3\) | 125 |
| Total Cubes | \(n^3\) | \(7^3\) | 343 |
We calculated the number of small cubes with one painted face. Let's quickly check the counts for other types to ensure the total adds up correctly:
Total cubes = \(8 + 60 + 150 + 125 = 343\). This matches the total number of small cubes \(7^3 = 343\).
The number of smaller cubes with only one face painted is 150.
| Number of Painted Faces | Location on Original Cube | Formula (where \(n\) is the number of small cubes along an edge) |
|---|---|---|
| 3 | Corners | 8 |
| 2 | Edges (excluding corners) | \(12(n-2)\) |
| 1 | Faces (excluding edges and corners) | \(6(n-2)^2\) |
| 0 | Interior | \((n-2)^3\) |
These formulas are valid when the large cube is painted on all 6 faces and \(n > 2\).
Painted cube problems are common in spatial reasoning and quantitative aptitude tests. They require you to visualize how a 3D object is divided and how properties (like paint) are distributed. The key is to understand the different locations within the large cube (corners, edges, faces, interior) and how these relate to the number of exposed faces before cutting.
For variations of this problem, consider:
In cases where not all faces are painted, you need to analyze which specific small cubes (based on their original position) would receive paint. For example, if only 5 faces are painted, the cubes on the unpainted face will have 0 painted faces instead of 1 (if they were face cubes), 1 instead of 2 (if they were edge cubes connected to the unpainted face), and 2 instead of 3 (if they were corner cubes connected to the unpainted face). Cubes on edges or faces not connected to the unpainted face would retain their original number of painted faces.
Mastering the standard cube-cutting formulas for all faces painted provides a strong foundation for tackling these more complex variations.
A cube of side 80 cm is painted yellow on all the faces and then cut into smaller cubes of sides 8 cm each. Find the number of smaller cube having all the three faces painted.
A cube of side 18 cm is painted yellow on all the faces and then cut into smaller cubes of sides 3 cm each. Find the number of smaller cubes that have only two faces painted.
A cube of side 12 cm is painted green on all the faces and then cut into smaller cubes of sides 2 cm each. Find the number of smaller cubes that have only one face painted.
Four friends J, Q, B and Z rolled the dice in alphabetical order.
The scores were:
1st round: 3, 2, 5, 2
2nd round: 1, 5, 1, 4
3rd round: 4, 2, 1, 1
If each point on the dice would get 10 points, who won the maximum points after 3 rounds?
Six numbers, 1, 2, 3, 4, 5, and 6, are written on the different faces of a dice. Three different positions of the same dice are shown (Figures 1-3). Find the number on the face opposite to the face showing ‘3’.
