This problem involves calculating the number of boys behind a specific student (Rohan) in a class, considering the total number of students, the ratio of boys to girls, and Rohan's rank from the top, along with the number of girls ahead of him.
We are given:
Let '$G$' be the number of girls and '$B$' be the number of boys.
From the given information, we can set up the following equations:
Now, substitute the second equation into the first:
\((2G) + G = 120\)
\(3G = 120\)
\(G = \frac{120}{3}\)
\(G = 40\)
So, there are 40 girls in the class.
Now, calculate the number of boys:
\(B = 2G = 2 \times 40 = 80\)
Therefore, there are 80 boys in the class.
Rohan is ranked 28th from the top. This means there are 27 students ahead of him.
Total students ahead of Rohan = Rank - 1
Total students ahead of Rohan = \(28 - 1 = 27\)
We know that out of the 27 students ahead of Rohan:
To find the number of boys ahead of Rohan, subtract the number of girls ahead from the total students ahead:
Number of boys ahead of Rohan = (Total students ahead of Rohan) - (Number of girls ahead of Rohan)
Number of boys ahead of Rohan = \(27 - 18 = 9\)
So, there are 9 boys ahead of Rohan.
We need to find the number of boys behind Rohan. Assuming Rohan is a boy (as the question asks for the number of *boys* behind him, implying his inclusion or exclusion is relevant to the count of boys):
The number of boys behind Rohan is the total number of boys minus the boys ahead of him and Rohan himself.
Number of boys behind Rohan = (Total boys) - (Boys ahead of Rohan) - 1 (Rohan)
Number of boys behind Rohan = \(80 - 9 - 1 = 70\)
| Category | Count |
|---|---|
| Total Students | 120 |
| Total Girls (G) | 40 |
| Total Boys (B) | 80 |
| Rohan's Rank (from top) | 28 |
| Students Ahead of Rohan | 27 |
| Girls Ahead of Rohan | 18 |
| Boys Ahead of Rohan | 9 |
| Boys Behind Rohan | 70 |
Therefore, there are 70 boys behind Rohan.
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ii. He must visit B before D.
iii. The third hospital he visits must be C.
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Who won the competition?