We are given two circles and need to find a point of intersection.
$\\( (x^2 - 2x + y^2 - 2y + 1) - (x^2 - x + y^2) = 0 \\)$
$\\{-x - 2y + 1 = 0 \\)$
Solve for $x$: $\\(x = 1 - 2y \\)$
$\\( (1 - 2y)^2 - (1 - 2y) + y^2 = 0 \\)$
$\\( (1 - 4y + 4y^2) - 1 + 2y + y^2 = 0 \\)$
$\\(5y^2 - 2y = 0 \\)$
Factor: $\\(y(5y - 2) = 0 \\)$
Possible $y$ values: $\\(y = 0 \\)$ or $\\(y = 2/5 = 0.4 \\)$.
In the given figure, PQRS is a square of side 2 cm and PLMN is a rectangle. The corner L of the rectangle is on the side QR. Side MN of the rectangle passes through the corner S of the square.
What is the area (in cm²) of the rectangle PLMN?
Note: The figure shown is representative.

A regular dodecagon (12-sided regular polygon) is inscribed in a circle of radius $r$ cm as shown in the figure. The side of the dodecagon is $d$ cm. All the triangles (numbered 1 to 12) in the figure are used to form squares of side $r$ cm and each numbered triangle is used only once to form a square.
The number of squares that can be formed and the number of triangles required to form each square, respectively, are:
Note: The figure shown is representative.
Let $S$ be the portion of the plane $z = 2x + 2y - 100$ which lies inside the cylinder $x^2 + y^2 = 1$. If the surface area of $S$ is $\alpha\pi$, then the value of $\alpha$ is equal to ________.