This problem involves calculating the final speed of an object undergoing free fall. We can use the basic equations of motion under constant acceleration (gravity in this case).
Physics Principles for Free Fall
When an object falls under gravity without air resistance, its acceleration is constant and equal to the acceleration due to gravity, '\(g\)'. The initial velocity (\(u\)) is 0 m/s if the object is dropped from rest.
Calculating Final Speed
We can use the first equation of motion:
\(v = u + at\)
Where:
- \(v\) is the final speed (what we need to find).
- \(u\) is the initial speed.
- \(a\) is the acceleration.
- \(t\) is the time.
Applying Given Values
From the question:
- The car falls off a ledge, so the initial speed \(u = 0 \, \text{m/s}\).
- The time taken to hit the ground is \(t = 0.6 \, \text{s}\).
- The acceleration due to gravity is given as \(g = 10 \, \text{m/s}^2\). Since the car is falling downwards, the acceleration \(a = g = 10 \, \text{m/s}^2\).
Determining the Car's Speed
Substitute the values into the equation:
\(v = 0 \, \text{m/s} + (10 \, \text{m/s}^2) \times (0.6 \, \text{s})\)
\(v = 10 \times 0.6 \, \text{m/s}\)
\(v = 6 \, \text{m/s}\)
Conclusion
The car's speed on striking the ground is 6 m/s.
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On the basis of which principle does soap clean surfaces?
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What special name is given to the frictional force exerted by a fluid?
