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Question

A car falls off a ledge and drops to the ground in 0.6 s. Take g = 10 m/s². What is the car’s speed on striking the ground?

This question was previously asked in
RRB ALP 2025 CBT 2 Wiremen Question Paper (28-Jul-2026) (Shift 2)
The correct answer is
6 m/s

This problem involves calculating the final speed of an object undergoing free fall. We can use the basic equations of motion under constant acceleration (gravity in this case).

Physics Principles for Free Fall

When an object falls under gravity without air resistance, its acceleration is constant and equal to the acceleration due to gravity, '\(g\)'. The initial velocity (\(u\)) is 0 m/s if the object is dropped from rest.

Calculating Final Speed

We can use the first equation of motion:

\(v = u + at\)

Where:

  • \(v\) is the final speed (what we need to find).
  • \(u\) is the initial speed.
  • \(a\) is the acceleration.
  • \(t\) is the time.

Applying Given Values

From the question:

  • The car falls off a ledge, so the initial speed \(u = 0 \, \text{m/s}\).
  • The time taken to hit the ground is \(t = 0.6 \, \text{s}\).
  • The acceleration due to gravity is given as \(g = 10 \, \text{m/s}^2\). Since the car is falling downwards, the acceleration \(a = g = 10 \, \text{m/s}^2\).

Determining the Car's Speed

Substitute the values into the equation:

\(v = 0 \, \text{m/s} + (10 \, \text{m/s}^2) \times (0.6 \, \text{s})\)

\(v = 10 \times 0.6 \, \text{m/s}\)

\(v = 6 \, \text{m/s}\)

Conclusion

The car's speed on striking the ground is 6 m/s.

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