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Question

A car decreases its speed from 40 m/s to 20 m/s in 5 s. Find the acceleration of the car.

This question was previously asked in
RRB NTPC 2024 Undergraduate CBT 1 Question Paper (29-Aug-2025) (Shift 1)
The correct answer is

$-4 m/s^2$

Acceleration Calculation for a Changing Speed

This problem asks us to find the acceleration of a car when its speed changes over a specific period. Acceleration is the rate at which an object's velocity changes over time.

Understanding the Variables

  • Initial Speed (\(u\)): The speed the car starts with. Here, \(u = 40\) m/s.
  • Final Speed (\(v\)): The speed the car ends with. Here, \(v = 20\) m/s.
  • Time (\(t\)): The duration over which the speed changes. Here, \(t = 5\) s.
  • Acceleration (\(a\)): The value we need to find.

Formula for Acceleration

Acceleration is calculated using the formula:

\( a = \frac{v - u}{t} \)

Where:

  • \(a\) is acceleration
  • \(v\) is the final velocity
  • \(u\) is the initial velocity
  • \(t\) is the time interval

Step-by-Step Calculation

  1. Identify the given values:
    • Initial speed, \(u = 40\) m/s
    • Final speed, \(v = 20\) m/s
    • Time, \(t = 5\) s
  2. Substitute the values into the acceleration formula:

    \( a = \frac{20 \text{ m/s} - 40 \text{ m/s}}{5 \text{ s}} \)

  3. Calculate the change in speed:

    \( v - u = 20 - 40 = -20 \text{ m/s} \)

    The negative sign indicates that the speed is decreasing.

  4. Divide the change in speed by the time taken:

    \( a = \frac{-20 \text{ m/s}}{5 \text{ s}} \)

  5. Determine the final acceleration value:

    \( a = -4 \text{ m/s}^2 \)

Conclusion

The acceleration of the car is \( -4 \text{ m/s}^2 \). The negative sign signifies that the car is decelerating or slowing down.

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