A can do a piece of work in 20 days. He worked for 8 days. Then B alone finishes the remaining work in 12 days. In how many days can B complete the whole work alone?
20
Work done by A in 8 days = \(\frac{8}{20}=\frac{2}{5}\).
Remaining work = \(1-\frac{2}{5}=\frac{3}{5}\).
B does \(\frac{3}{5}\) of the work in 12 days, so B’s whole work takes \(12\times\frac{5}{3}=20\) days.
Hence, B alone can complete the whole work in 20 days.
Similar Questions
A can complete a work in 12 days, and B in 16 days. They work together for 3 days. How much work is left?
If A works twice as fast as B, and A can complete a task in 10 days, how many days will it take for B to complete the task?
Important Questions from Work Efficiency
A man completes 7/8 of a job in 21 days. How many more days will it take him to finish the job if quantum of work further increased by 50%?
24 men and 12 women can do a piece of work in 30 days. In how many days can 12 men and 24 women do the same piece of work?
A and B together can do a piece of work in 4 days, B and C can do it in 6 days, A and C can do it in 8 days. Then A, B and C together can do the same work in :-
A can complete 50% of a work in 9 days and B can do 25% of the work in 9 days, if they work alone. If they work together then how much work (in percentage) can be completed in 6 days?
A is thrice as good a workman as B. C alone takes 48 days to paint a house. All three A, B and C working together take 16 days to paint the house. It will take how many days for A alone to paint the house?
