This problem involves calculating the recoil speed of a gun when a bullet is fired from it. We can solve this using the principle of conservation of linear momentum.
Principle: The total momentum of a system remains constant if no external forces act upon it. In this case, before firing, the gun and bullet are at rest, so the initial momentum is zero. After firing, the momentum of the bullet and the gun must sum to zero.
Given Data:
According to the conservation of momentum:
$m_b v_b + m_g v_g = 0$We need to find the recoil speed ($v_g$). Rearranging the equation:
$v_g = - \frac{m_b v_b}{m_g}$Substitute the given values into the equation:
$v_g = - \frac{(0.01 \ kg) \times (100 \ m/s)}{1 \ kg}$ $v_g = - \frac{1 \ kg \cdot m/s}{1 \ kg}$ $v_g = -1 \ m/s$The negative sign indicates that the gun moves in the opposite direction to the bullet. The recoil speed is the magnitude of this velocity.
Recoil speed = $|v_g| = |-1 \ m/s| = 1 \ m/s$.
A thin uniform rod ($X$) of mass $M$ and length $L$ is pivoted at a height $\left(\frac{L}{3}\right)$ as shown in the figure. The rod is allowed to fall from a vertical position and lie horizontally on the table. The angular velocity of this rod when it hits the table top, is __________.
($g = \text{gravitational acceleration}$)

The pulley shown in figure is made using a thin rim and two rods of length equal to diameter of the rim. The rim and each rod have a mass of $M$. Two blocks of mass of $M$ and $m$ are attached to two ends of a light string passing over the pulley, which is hinged to rotate freely in vertical plane about its center. The magnitudes of the acceleration experienced by the blocks is __________
(assume no slipping of string on pulley).
A thin uniform rod ($X$) of mass $M$ and length $L$ is pivoted at a height $\left(\frac{L}{3}\right)$ as shown in the figure. The rod is allowed to fall from a vertical position and lie horizontally on the table. The angular velocity of this rod when it hits the table top, is __________.
($g = \text{gravitational acceleration}$)
