Physics Formula for Constant Acceleration
For an object moving with constant acceleration (\(a\)), the relationship between initial speed (\(V_0\)), final speed (\(v\)), and the distance travelled (\(x\)) is given by the kinematic equation:
\(v^2 = V_0^2 + 2ax\)
Final Speed Calculation
Given the parameters:
- Initial speed: \(V_0\)
- Constant acceleration: \(a\)
- Distance travelled: \(x\)
Based on the standard kinematic equation \(v^2 = V_0^2 + 2ax\), the final speed \(v\) can be determined. Analyzing the provided options, the expression matching the required format for final speed calculation under constant acceleration is presented in Option B.
Option B: \(V_0 + 2ax\)
Similar Questions
- A ball thrown up vertically returns to the ground after 10 second. Find the velocity with which it was thrown up? (if g = 10 m/s2).
- A ball is thrown vertically upward with a speed of 30 m/s. The magnitude of its displacement after 4 s will be ______ (Take \(g = 10 \text{ m/s}^2\).)
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Important Questions from Kinematic equations for uniformly accelerated motion
Which of the following is an equation of motion?
I. u = v + at
II. 2as = v 2– u 2
- A ball is thrown vertically upward with a speed of 40 m/s. The time taken by the ball to reach the maximum height would be approximately
- A ball thrown up vertically returns to the ground after 10 second. Find the velocity with which it was thrown up? (if g = 10 m/s2).
If the distance travelled by a body in the $n^{th}$ second is given by $(7 + 5n)$ m, then find the initial velocity and acceleration of the body respectively.
Which of the following is an equation of motion?
I. u = v + at
II. 2as = v 2– u 2
