Floor Numbering Logic

The goal is to determine who lives on the different floors (1 to 6) using the provided clues.

Clue Interpretation

• U's Position: U lives on an odd-numbered floor (3 or 5), excluding floor 1.
• B-U-A Block: B lives immediately above U, and A lives immediately below U. This forms a fixed sequence B-U-A.
• K-D Block: K lives immediately above D. This forms a fixed sequence K-D.
• D's Constraint: D cannot live on the lowermost floor (floor 1).
• U-P Gap: There is exactly one person living between U and P.

Building Block Deduction (B-U-A & K-D)

The B-U-A block requires three consecutive floors. The K-D block requires two consecutive floors. D cannot be on floor 1.

Floor Assignment Scenarios

Consider the two possible positions for U (floor 3 or 5):

• Scenario 1: U on Floor 5. This places B on 6 and A on 4 (B-U-A block = 6-5-4). For the U-P gap, P must be on floor 3 (A is between them). The remaining floors are 1 and 2. K-D must occupy these floors, so D=1, K=2. This violates the rule that D is not on floor 1. Scenario 1 is invalid.
• Scenario 2: U on Floor 3. This places B on 4 and A on 2 (B-U-A block = 4-3-2). Now consider the U-P gap. P could be on floor 1 (A is between U and P) or floor 5 (B is between U and P).

Evaluating the U-P gap possibilities within Scenario 2:

• Sub-scenario 2a: P on Floor 5. Floors occupied: A(2), U(3), B(4), P(5). Remaining floors: 1 and 6. K-D must fit here with K above D. So D=1, K=6. This violates D not being on floor 1. Sub-scenario 2a is invalid.
• Sub-scenario 2b: P on Floor 1. Floors occupied: P(1), A(2), U(3), B(4). Remaining floors: 5 and 6. K-D must fit here with K above D. So D=5, K=6. This satisfies all conditions, including D not being on floor 1. This is the valid scenario.

Final Floor Plan

The confirmed arrangement is:

• Floor 6: K
• Floor 5: D
• Floor 4: B
• Floor 3: U
• Floor 2: A
• Floor 1: P

Identify Floor 2 Resident

According to the deduced floor plan, A resides on Floor 2.