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Question

A 5 N force is defined when a mass of 10 kg is accelerated with

This question was previously asked in
NDA I 2022 GAT Previous Year Paper (10-Apr-2022)
The correct answer is 0.5 m/s 2

Understanding Force, Mass, and Acceleration

This problem involves the fundamental relationship between force, mass, and acceleration, which is described by Newton's second law of motion. Newton's second law states that the acceleration of an object is directly proportional to the net force acting upon it and inversely proportional to its mass. It's often expressed with the formula:

\(F = ma\)

Where:

  • \(F\) is the net force acting on the object (measured in Newtons, N).
  • \(m\) is the mass of the object (measured in kilograms, kg).
  • \(a\) is the acceleration of the object (measured in meters per second squared, m/s\(^2\)).

Calculating Acceleration using Newton's Second Law

We are given the following information:

  • Force (\(F\)) = 5 N
  • Mass (\(m\)) = 10 kg

We need to find the acceleration (\(a\)). We can rearrange Newton's second law formula (\(F = ma\)) to solve for acceleration:

\(a = \frac{F}{m}\)

Now, substitute the given values into the formula:

\(a = \frac{5 \, \text{N}}{10 \, \text{kg}}\)

Performing the division:

\(a = 0.5 \, \frac{\text{N}}{\text{kg}}\)

Let's consider the units. The Newton (N) is defined as the force required to accelerate a one-kilogram mass at a rate of one meter per second squared. So, 1 N = 1 kg⋅m/s\(^2\). Substituting this into our unit calculation:

\(\frac{\text{N}}{\text{kg}} = \frac{\text{kg} \cdot \text{m/s}^2}{\text{kg}} = \text{m/s}^2\)

Thus, the acceleration is:

\(a = 0.5 \, \text{m/s}^2\)

Comparing Calculation with Options

We calculated the acceleration to be 0.5 m/s\(^2\). Let's examine the given options:

  1. 5.0 cm/s\(^2\)
  2. 0.5 m/s\(^2\)
  3. 0.5 cm/s\(^2\)
  4. 5.0 m/s\(^2\)

We need to make sure the units match. Our result is in m/s\(^2\). Let's convert the options in cm/s\(^2\) to m/s\(^2\) for comparison, remembering that 1 m = 100 cm, so 1 cm = 0.01 m.

  • Option 1: 5.0 cm/s\(^2\) = 5.0 \(\times\) 0.01 m/s\(^2\) = 0.05 m/s\(^2\). (This does not match 0.5 m/s\(^2\))
  • Option 2: 0.5 m/s\(^2\). (This matches our calculated value)
  • Option 3: 0.5 cm/s\(^2\) = 0.5 \(\times\) 0.01 m/s\(^2\) = 0.005 m/s\(^2\). (This does not match 0.5 m/s\(^2\))
  • Option 4: 5.0 m/s\(^2\). (This does not match 0.5 m/s\(^2\))

The calculated acceleration of 0.5 m/s\(^2\) matches Option 2.

Revision Table: Force, Mass, and Acceleration Concepts

Concept Definition Unit (SI) Relation (from F=ma)
Force (\(F\)) A push or pull that can cause a change in motion (acceleration) Newton (N) \(F = ma\)
Mass (\(m\)) A measure of the amount of matter in an object; resistance to acceleration (inertia) Kilogram (kg) \(m = \frac{F}{a}\)
Acceleration (\(a\)) The rate of change of velocity Meter per second squared (m/s\(^2\)) \(a = \frac{F}{m}\)

Additional Information on Newton's Laws and Units

Newton's second law is a cornerstone of classical mechanics. It quantitatively describes how forces affect motion. The direction of the acceleration is always in the same direction as the net force.

The SI unit for force, the Newton (N), is a derived unit. It is named after Sir Isaac Newton. As we saw in the calculation, 1 Newton is equivalent to 1 kilogram-meter per second squared (1 N = 1 kg⋅m/s\(^2\)). This relationship is directly derived from Newton's second law, \(F=ma\), where mass is in kg and acceleration is in m/s\(^2\).

Understanding units and being able to convert between them (like cm to m) is crucial in physics problem-solving to ensure that calculations are done with consistent units within the same system (e.g., SI units).

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