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Question

A 0–200 V voltmeter has a guaranteed accuracy of ±1% of full-scale reading. If the instrument indicates 50 V, the actual voltage being measured lies between:

This question was previously asked in
RRB Technician 2026 Grade 3 Question Paper (7-Oct-2026) (Shift 3)
The correct answer is

48.0 V and 52.0 V

When accuracy is specified as a percentage of full-scale reading, the limiting error in volts is the same at every point on the scale.

Limiting error = \(\pm 1\% \times 200\ \text{V} = \pm 2\ \text{V}\).

For an indicated value of 50 V, the true voltage lies within \(50 \pm 2\ \text{V}\).

Lower limit = 50 − 2 = 48 V and upper limit = 50 + 2 = 52 V. (At this reading the relative error is \(\frac{2}{50} \times 100 = 4\%\).)

Hence, the answer is 48.0 V and 52.0 V.

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