\(-75 \times 109\) is not the same as:
\((-75) \times 9 + 100\)
The number 109 can be written as \(100 + 9\), so \(-75 \times 109 = -75 \times (100+9) = (-75)\times 100 + (-75)\times 9\), which matches \((-75) \times 9 + (-75) \times 100\).
Also, \(-75 = -70 - 5\), so \((-70-5)\times 109\) is the same product written differently.
The expression \((-75) \times 9 + 100\) replaces the second term \((-75)\times 100\) with a plain \(+100\), dropping the multiplication by \(-75\), so it no longer equals \(-75 \times 109\).
Hence, the expression that is not the same as \(-75 \times 109\) is \((-75) \times 9 + 100\).
Important Questions from Integers
How many three digit whole numbers are there between 75 and 405?
Find the number of integers between $1$ and $150$ (inclusive) having $7$ as one of the digits but which are not divisible by $7$.
Integers are listed from 700 to 1000. In how many integers is the sum of the digits 10 ?
Using 2, 2, 3, 3, 3 as digits, how many distinct numbers greater than 30000 can be formed ?
Consider the following statements :
1. The sum of 5 consecutive integers can be 100.
2 The product of three consecutive natural numbers can be equal to their sum.
Which of the above statements is/are correct ?
