The problem states that 1 litre (L) of water weighs 1 kilogram (kg). This establishes the density of water.
We know that 1 mL is equivalent to 1 cubic centimetre (cm$^3$). So, 1 cm$^3$ of water weighs 1 g.
The question asks for the volume in cubic millimetres (mm$^3$) that weighs 0.1 g.
First, find the volume in cm$^3$ for 0.1 g of water:
Using the density relationship (1 g per cm$^3$):
$ \text{Volume} = \frac{\text{Mass}}{\text{Density}} = \frac{0.1 \text{ g}}{1 \text{ g/cm}^3} = 0.1 \text{ cm}^3 $Next, convert this volume from cm$^3$ to mm$^3$. We know that 1 cm = 10 mm.
Therefore, 1 cm$^3$ = (10 mm)$^3$ = 1000 mm$^3$.
Now convert 0.1 cm$^3$ to mm$^3$:
$ 0.1 \text{ cm}^3 = 0.1 \times 1000 \text{ mm}^3 = 100 \text{ mm}^3 $Thus, 100 mm$^3$ of water will weigh 0.1 g.
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