\(3 \times 6 + 2 - 4 \div 8 = 13\)
The problem requires us to interchange two mathematical signs in the given equation to make it true. The original equation is:
\(3 \times 6 + 2 - 4 \div 8 = 13\)
First, let's evaluate the original equation using the order of operations (PEMDAS/BODMAS):
The original equation evaluates to \(19.5\), not \(13\). We need to test the given options.
The correct answer indicates that interchanging the division (\(\div\)) and plus (\(+\)) signs corrects the equation. Let's verify this.
The signs to be interchanged are \(\div\) and \(+\).
The original equation is: \(3 \times 6 + 2 - 4 \div 8 = 13\).
After interchanging \(\div\) and \(+\), the equation becomes:
\(3 \times 6 \div 2 - 4 + 8 = 13\)
Now, let's evaluate this new equation using the order of operations:
The equation now correctly evaluates to \(13\). Therefore, interchanging the \(\div\) and \(+\) signs is the correct solution.
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