Which two numbers from amongst the given options should be interchanged to make the given equation correct? 126 ÷ 23 – 138 ÷ ( 5 × 4 – 6) + 4 = 1
138 and 126
The question requires us to find a pair of numbers from the given options that, when swapped in the original equation, makes the equation true. The original equation is:
$\qquad 126 \div 23 - 138 \div (5 \times 4 - 6) + 4 = 1$
We will examine each option by swapping the numbers and evaluating the left side of the equation to see if it equals 1.
If we interchange the numbers 4 and 6 in the equation, the new equation becomes:
$\qquad 126 \div 23 - 138 \div (5 \times 6 - 4) + 6$
Evaluating the left side following the order of operations (BODMAS/PEMDAS):
$\qquad = 126 \div 23 - 138 \div (30 - 4) + 6$
$\qquad = 126 \div 23 - 138 \div 26 + 6$
Performing the divisions (approximately):
$\qquad \approx 5.478 - 5.308 + 6$
Performing subtraction and addition:
$\qquad \approx 0.17 + 6$
$\qquad \approx 6.17$
Since $6.17 \ne 1$, swapping 4 and 6 does not make the equation correct.
Let's interchange the numbers 138 and 126 in the equation. The new equation is:
$\qquad 138 \div 23 - 126 \div (5 \times 4 - 6) + 4$
Now, let's evaluate the left side step-by-step using the order of operations:
First, calculate the expression inside the parentheses:
$\qquad (5 \times 4 - 6) = (20 - 6) = 14$
Substitute this value back into the equation:
$\qquad 138 \div 23 - 126 \div 14 + 4$
Next, perform the divisions from left to right:
$\qquad 138 \div 23 = 6$
$\qquad 126 \div 14 = 9$
Substitute these results:
$\qquad 6 - 9 + 4$
Finally, perform the subtraction and addition from left to right:
$\qquad (6 - 9) + 4 = -3 + 4 = 1$
The left side evaluates exactly to 1, which is the value on the right side of the original equation. Thus, swapping 138 and 126 makes the equation correct.
Interpreting this as swapping the number 4 on the left side with the target result 1 on the right side, the equation we check if the original left side with 4 replaced by 1 equals the original right side's 1 replaced by 4. The left side becomes:
$\qquad 126 \div 23 - 138 \div (5 \times 4 - 6) + 1$
The equation we are checking becomes:
$\qquad 126 \div 23 - 138 \div (5 \times 4 - 6) + 1 = 4$
We already know $(5 \times 4 - 6) = 14$. So the left side evaluation is:
$\qquad = 126 \div 23 - 138 \div 14 + 1$
$\qquad \approx 5.478 - 9.857 + 1$
$\qquad \approx -4.379 + 1$
$\qquad \approx -3.379$
Since $-3.379 \ne 4$, swapping 4 and 1 does not make the equation correct under this interpretation.
If we interchange the numbers 23 and 138 in the equation, the new equation becomes:
$\qquad 126 \div 138 - 23 \div (5 \times 4 - 6) + 4$
Evaluating the left side:
$\qquad = 126 \div 138 - 23 \div (20 - 6) + 4$
$\qquad = 126 \div 138 - 23 \div 14 + 4$
Performing the divisions (approximately):
$\qquad \approx 0.913 - 1.643 + 4$
Performing subtraction and addition:
$\qquad \approx -0.73 + 4$
$\qquad \approx 3.27$
Since $3.27 \ne 1$, swapping 23 and 138 does not make the equation correct.
The table below summarizes the result of each interchange option:
| Numbers Swapped | Result of LHS Evaluation | Equation Correct? (Target = 1) |
|---|---|---|
| 4 and 6 | $\approx 6.17$ | No |
| 138 and 126 | $1$ | Yes |
| 4 and 1 (Interpreted as swapping 4 with the RHS 1, checking if LHS=4) | $\approx -3.379$ | No |
| 23 and 138 | $\approx 3.27$ | No |
The correct evaluation of mathematical expressions depends on following the standard order of operations. This ensures a consistent result for any given expression. A common acronym used to remember the order is BODMAS or PEMDAS.
In this problem, applying the order of operations was essential to correctly evaluate the equation after each proposed number swap.
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