In quantum mechanics, the behavior of electrons in atoms, like the Hydrogen atom, is described by wave functions, denoted by $\psi$. For a Hydrogen atom or any one-electron species, the wave function $\psi$ depends on the quantum numbers: the principal quantum number ($n$), the angular momentum quantum number ($l$), and the magnetic quantum number ($m_l$). The wave function can be separated into two parts:
The complete wave function is the product of these two parts: $\psi_{nlm_l}(r, \theta, \phi) = R_{nl}(r) \cdot Y_{lm_l}(\theta, \phi)$.
The question specifically asks about the 's' orbitals in the Hydrogen atom. For 's' orbitals, the angular momentum quantum number is $l=0$.
Therefore, the 's' orbital's characteristics (specifically its probability distribution) depend solely on the radial wave function and are independent of the angular wave function because the angular part is just a constant for $l=0$.
Let's analyze each statement based on this understanding:
This statement aligns perfectly with our understanding. Since $l=0$ for s orbitals, the angular part $Y_{00}$ is constant, making the orbital dependent only on the radial part $R_{n0}(r)$.
This is incorrect. While 's' orbitals have radial dependence, they are independent of the angular part ($\theta$ and $\phi$) because $l=0$. Angular dependence arises for orbitals with $l \geq 1$ (like p, d, f orbitals).
This is incorrect. 's' orbitals have a clear dependence on the radial wave function, which determines their size and energy levels. Dependence on angular functions starts with p orbitals ($l=1$), not that it *only* starts there.
This is the opposite of the actual situation. 's' orbitals are independent of the angular functions but are dependent on the radial function.
Based on the analysis, the first statement accurately describes the characteristics of the 's' orbital in the Hydrogen atom.
For a given system of resistors having resistances R, 2R, R$_0$ and 2R (shown in the figure), what will be the value of resistance of the resistor R$_0$, when there is NO current in the galvanometer G?
