p-block element from Period - 6 and Group - 14
To determine the group and period of the element in the Modern Periodic Table, we need to analyze the given electronic configuration of the ion: 4d^4 \ 5d^{10}. This configuration is typical of elements in the p-block, particularly in the heavy p-block elements.
Therefore, based on the electronic configuration and the periodic properties, the element is a p-block element from Period 6 and Group 14. This matches with option: p-block element from Period - 6 and Group - 14.
To further ensure the understanding, it is critical to grasp that in the periodic table, the filling order and the sequence of the periods and groups adhere to the Aufbau principle, where electrons occupy the lowest available energy orbital. Additionally, Period 6 involves both the filling of the 4f, 5d, and 6p orbitals, aligning with the given configuration.
For a given system of resistors having resistances R, 2R, R$_0$ and 2R (shown in the figure), what will be the value of resistance of the resistor R$_0$, when there is NO current in the galvanometer G?
