
The question asks to identify the kinetic model for non-growth associated product formation in bioprocesses. This type of product formation occurs independently of the cell growth rate.
The rate of product formation is generally expressed as:
\(\frac{dP}{dt} = q_p X\)
Where:
For non-growth associated kinetics, the specific productivity \(q_p\) is assumed to be constant over time, often denoted as \(k_p\). Therefore, the rate equation simplifies to:
\(\frac{dP}{dt} = k_p X\)
This implies:
The correct graphical representation should demonstrate this linear relationship between $P$ and $t$, particularly during the phase when $X$ is constant.
Option 3 is the correct representation because it clearly shows the linear accumulation of product ($P$) over time ($t$) during the stationary phase of biomass ($X$), which is the hallmark of non-growth associated product formation.
If the rate at which $E. coli$ divides is $0.5 \text{ h}^{-1}$, then its doubling time is _______________ h.
Let $y(t)$ be a bacterial population whose growth is given by
$ \frac{dy}{dt} = \lambda(y + 2) $
where $ \lambda $ is the growth rate constant. If $y(0) = 1$ and $y(1) = 4$, then the value of $ \lambda $ is
If the doubling time of a bacterial population is 3 hours, then its average specific growth rate during this period is _________ $h^{-1}$.
(Round off to two decimal places)