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Question

A microorganism is grown in a batch culture using glucose as a carbon source. The apparent growth yield is $0.5 \frac{\text{g biomass}}{\text{g substrate}}$. The initial concentrations of biomass and substrate are $2 \text{ g L}^{-1}$ and $200 \text{ g L}^{-1}$, respectively. Assuming that there is no endogenous metabolism, the maximum biomass concentration that can be achieved is ________ $\text{g L}^{-1}$.

Calculating Maximum Biomass Concentration

The maximum biomass concentration ($X_{max}$) in a batch culture, assuming no endogenous metabolism, can be determined using the apparent growth yield ($Y_{XS}$) and the initial concentrations of biomass ($X_0$) and substrate ($S_0$). The apparent growth yield relates the increase in biomass produced to the amount of substrate consumed.

Growth Yield Concept

The apparent growth yield ($Y_{XS}$) is defined as the change in biomass ($\Delta X$) divided by the change in substrate ($\Delta S$):

$Y_{XS} = \frac{\Delta X}{\Delta S}$

In this scenario, $\Delta X = X_{max} - X_0$ and $\Delta S = S_0 - S_{final}$. Since maximum biomass is achieved when the substrate is nearly depleted (assuming it's the limiting nutrient), $S_{final} \approx 0$. Therefore, $\Delta S \approx S_0$.

The relationship simplifies to:

$Y_{XS} = \frac{X_{max} - X_0}{S_0}$

Step-by-Step Calculation

  1. Identify Given Values:
    • Apparent growth yield, $Y_{XS} = 0.5 \frac{\text{g biomass}}{\text{g substrate}}$
    • Initial biomass concentration, $X_0 = 2 \frac{\text{g}}{\text{L}}$
    • Initial substrate concentration, $S_0 = 200 \frac{\text{g}}{\text{L}}
  2. Rearrange the formula to solve for $X_{max}$:

    $X_{max} - X_0 = Y_{XS} \times S_0$

    $X_{max} = X_0 + (Y_{XS} \times S_0)$

  3. Substitute the given values into the formula:

    $X_{max} = 2 \frac{\text{g}}{\text{L}} + \left( 0.5 \frac{\text{g biomass}}{\text{g substrate}} \times 200 \frac{\text{g substrate}}{\text{L}} \right)$

  4. Calculate the substrate consumed contribution to biomass:

    $0.5 \times 200 = 100 \frac{\text{g biomass}}{\text{L}}$

  5. Calculate the final maximum biomass concentration:

    $X_{max} = 2 \frac{\text{g}}{\text{L}} + 100 \frac{\text{g}}{\text{L}} = 102 \frac{\text{g}}{\text{L}}$

The maximum biomass concentration that can be achieved is $102 \frac{\text{g}}{\text{L}}$.

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Important Questions from Kinetics of Cell Growth Substrate Utilization and Product Formation

  1. If the rate at which $E. coli$ divides is $0.5 \text{ h}^{-1}$, then its doubling time is _______________ h.

  2. Which of the following factors can affect the growth of a microbial culture in a batch cultivation process?
  3. Let $y(t)$ be a bacterial population whose growth is given by 

          $ \frac{dy}{dt} = \lambda(y + 2) $ 

    where $ \lambda $ is the growth rate constant. If $y(0) = 1$ and $y(1) = 4$, then the value of $ \lambda $ is

  4. If the doubling time of a bacterial population is 3 hours, then its average specific growth rate during this period is _________ $h^{-1}$. 

    (Round off to two decimal places)

  5. Which one of the following represents non-growth associated product formation kinetics in a bioprocess system? X and P denote viable cell and product concentrations, respectively.
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